I need help in numericals

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Answered Same Day Dec 22, 2021

Solution

Robert answered on Dec 22 2021

129 Votes

Solution
1.
Solution:
Let the potential at source of each transistor Q1 and Q2 is Vx
Cu
ent through Q1 is I1 and Through Q2 is Iss-I1
Writing cu
ent equation for Q1 we get

Output voltage
Case 1:
Solving this we get
I1=7.5 uA
Therefore V0=-10+(15-7.5)u*500k=-6.25 V
Case 2: when V1= 20 mV.
This will try to reduce the cu
ent through Q1 and cu
ent in Q2 starts increasing
For this case effective Vsg will decrease and hence
Substituting the values in the above equation we get
We get
I1=6.673 uA
V0=-5.83
Alternate Method:
Write cu
ent equation for both
anches:

I1=

=6.278 uA
V0=-10+(15-6.278)u*500k=-5.63 V
Case 3: Maximum voltage will appear at out put when Q1 goes to cut-off and all cu
ent passes
through Q2.
Therefore maximum
2,
Solution:
In this case upper part of circuit is just for biasing the differential...

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I need help in numericals

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