8.142
data: After removing outlier a)
22 22 90% CI
19 19 mean+- t(A/2,n-1)*(sd/sqrt(n))
24 24
31 31 MEAN= 25.82
29 29 sd= 7.71
29 29 n= 22
21 21 t(a/2,n-1)= 1.7207429028
15 15
27 27 lower 22.9914814933
23 23 upper 28.6485185067
37 37
31 31 c)
30 30 90% CI
26 26 mean+- t(A/2,n-1)*(sd/sqrt(n))
16 16
26 26 MEAN= 24.7619047619
12 12 sd= 6.0490062151
23 23 n= 21
48 22 t(a/2,n-1)= 1.7247182429
22 29
29 28 lower 22.485274311
28 upper 27.0385352128
9.116
Ho:Â the 2012 mean annual expenditure on apparel and services for consumer units in the North East is equal to the national mean of $1736
H1:Â the 2012 mean annual expenditure on apparel and services for consumer units in the North East is not equal to the national mean of $1736
Mean= 1,922.76Â
sd= 350.90
u= 1,736.00
n= 25.00
alpha= 5%
T(a/2,n-1)
t(0.05/2,25-1)
2.064
T = (mean-u)/(sd/sqrt(n))
2.6611646086
2.6612
P-value
2*(1-P(T<|t|)
2*(1-P(T
T.DIST.2T(abs(2.6612),25-1)
0.0137
With (t=2.6612, p<5%),I reject the null hypothesis at 5% level of significance. And conclude that the 2012 mean annual expenditure on apparel and services for consumer units in the North East is not equal to the national mean of $1736
9.154
data: R Sorted data ho: median is 7.5
8.7 2nd 5.4 h1: median is NOT 7.5
7.5 1st 5.7
5.4 1st 5.8
13.9 2nd 6.1
7.9 2nd 7.3
5.8 1st 7.5
9.3 2nd 7.9
8.9 2nd 8.3
8.3 2nd 8.7
9.3 2nd 8.9
5.7 1st 9.3
6.1 1st 9.3 n1= 6
11.7 2nd 11.7 n2= 8
7.3 1st 13.9 u= 90
sd^2= 60
R= 8
z= -10.5861544796
p-value= 2*(1-P(Z<=|z|)
0.000000
since p-value<5%, I reject Ho and conclude that
median is NOT 7.5
10.46
Ho:Â there is no significant difference in the average sense of direction in males and females.
H1:Â males have a better average sense of direction as compared to female
Sample 1 Samplen 2
N= 30 30
Mean= 37.6 55.8
S= 38.5 48.3
s^2/n 49.4083 77.763
T =
= (Xbar1-Xbar2)/SQRT(S1^2/N1 + S2^2/N2)
= (37.6-55.8)/SQRT(49.4083+77.763)
-1.6139
df=
(s1^2/n1 + s2^2/n2)^2/((s1^2/n1)^2/(n1-1) + (s2^2/n2)^2/(n2-1))
(49.4083+77.763)^2/(49.4083^2/(30-1) + 77.763^2/(30-1))
186
Alpha= 1%
P-value
P(T>t)
(1-P(T<-1.6139)
T.DIST.RT(-1.6139,186)
0.945877834
With (t=-1.61, p>5%),I fail to reject the null hypothesis at 5% level of significance and conclude that there is no significant difference in the average sense of direction in males and...