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HW 12 Problem 1. In a certain wireless channel, the delay spread TD=10µsec and the maximum Doppler spread fd=0.2 kHz. The maximum propagation attenuation is 40dB. The total power available at the...

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HW 12 Problem 1. In a certain wireless channel, the delay spread TD=10µsec and the maximum Doppler spread fd=0.2 kHz. The maximum propagation attenuation is 40dB. The total power available at the transmitter is 1.08Watt. (Hint: i.e., the minimum received signal power is 0.108 mWatt.) The total bandwidth is 2 MHz For the OFDM receiver, the received noise power density is 0.1µWatts/MHz. The total intercarrier interference power (for all subcarriers combined) is (fdT)2 mWatts where T is the OFDM symbol duration. a.
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HW 12 Problem 1. In a certain wireless channel, the delay spread T =10µsec and the maximum Doppler D spread f =0.2 kHz. The maximum propagation attenuation is 40dB. d The total power available at the transmitter is 1.08Watt. (Hint: i.e., the minimum received signal power is 0.108 mWatt.) The total bandwidth is 2 MHz For the OFDM receiver, the received noise power density is 0.1µWatts/MHz. The total 2 intercarrier interference power (for all subcarriers combined) is (f T) mWatts where T is d the OFDM symbol duration. a.) what is the minimum guard time interval for preventing intersymbol interference? b.) what is the maximum data rate (BPSK signaling) where minimum SINR is 40 (in linear scale)? Problem 2 Let the original symbol duration T be 0.1msec and the number of subcarrier is 16 (k=0:15). Guard time T for cyclic prefix is 0.02msec. The combined symbol period T G s becomes 0.12msec. Let the OFDM signal go though a time varying channel with the following 2-path model: N -- jf 2(pt ft) nn Hf(,t)= ae with N=2, a =1 for n=1,2, t =0, t =0.01msec, n 1 2 ? n n=1 th a.) For f =200Hz and f =-200Hz, find the ICI at the 8 carrier (k=7) for m=0,1,2, …,6. 1 2 m th b.) For f =600Hz and f =-600Hz, find the ICI at the 8 carrier (k=7) for m=0,1,2, …,6 1 2 m

Answered Same Day Dec 23, 2021

Solution

David answered on Dec 23 2021
118 Votes
HW 12
Problem 1.
In a certain wireless channel, the delay spread TD=10μsec and the maximum
Doppler
spread fd=0.2 kHz. The maximum propagation attenuation is 40dB.
The total power available at the transmitter is 1.08Watt. (Hint: i.e., the
minimum received
signal power is 0.108 mWatt.) The total bandwidth is 2 MHz
For the OFDM receiver, the received noise power density is 0.1μWatts/MHz.
The total
interca
ier interference power (for all subca
iers combined) is (fdT)2
mWatts where T is
the OFDM symbol duration.
a.) what is the minimum guard time interval for preventing intersymbol
interference?
.) what is the maximum data rate (BPSK signaling) where minimum...
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