help with the attached

Answered Same DayFeb 26, 2020

Solution.docxSOLUTION 2:

Given that:

Also,

Therefore,

SOLUTION 3:

Consider the image below:

We will find the field at point P inside the hole.

The cu

ent density J is given by:

Applying Ampere’s Law, we get:

At two different points as shown, using the above law, we get:

Therefore, we get:

Since, both the fields are not in same direction, the field vectors are superimposed.

Consider the image below:

Therefore,

From diagram, we can observe:

Thus, the magnitude of field is:

SOLUTION 4:

The solutions obtained in the said article, when combined with a vortex, gives the flow past a rotating cylinder. The superimposed stream function now consists of three components:

,

Where, ‘a’ is the radius of cylinder.

The pressure distribution can be obtained using Bernoulli Equation, as:

The drag force is obtained by integrating pressure over the cylinder surface.

We get:

Similarly, lift force is obtained by integrating...

Given that:

Also,

Therefore,

SOLUTION 3:

Consider the image below:

We will find the field at point P inside the hole.

The cu

ent density J is given by:

Applying Ampere’s Law, we get:

At two different points as shown, using the above law, we get:

Therefore, we get:

Since, both the fields are not in same direction, the field vectors are superimposed.

Consider the image below:

Therefore,

From diagram, we can observe:

Thus, the magnitude of field is:

SOLUTION 4:

The solutions obtained in the said article, when combined with a vortex, gives the flow past a rotating cylinder. The superimposed stream function now consists of three components:

,

Where, ‘a’ is the radius of cylinder.

The pressure distribution can be obtained using Bernoulli Equation, as:

The drag force is obtained by integrating pressure over the cylinder surface.

We get:

Similarly, lift force is obtained by integrating...

SOLUTION.PDF## Answer To This Question Is Available To Download

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