FUll-Flop Characteristic Tables(a) JK Flip-Flop (b) SR Flip~FlopJ K Q (t + 1) Operation S R Q(t+1}...

Question

FUll-Flop Characteristic Tables(a) JK Flip-Flop (b) SR Flip~FlopJ K Q (t + 1) Operation S R Q(t+1} Operation0 a Q(t) No change 0 0 •Q(t) No chanceD0 1 a Reset 0 1 0 Reset0 1 Set 1 0 1 SetQ(n Complement 1. 1 '? Undefined(c) D Flip-Flop (D Q (t + 1) Operation T Q (t + 1) Operation'"0 0 Reset 0
	
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(b) SR Flip~Flop
(a) JK Flip-Flop
J K Q (t + 1) Operation S R Q(t+1} Operation
0 a No change 0 0 No chance
Q(t) •Q(t)
D
a Reset 0 1 0 Reset
0 1
0 1 Set 1 0 1 Set
1 Undefined
Complement 1. '?
Q(n
(-
-
y
L)'
x
y
K
X J Q'
Q
0
1
1
0
1
-,Question 2 (20 prs) 555 Timers
A. Given the following 555 timer inAstable mode, where Rl = 50k, R2 = 10k and Cl =
0.001 uP and C2 = 0.01 uF
vee
OUTPUT
IC1
2 3
Q
TR 0::
7
R DIS
L....1c
5 6
CV THR
I)~ o~
_k2
GND V+
.-1 tL-- a:
_...-r- g:~
LM555N
,,.
GND
f'
,,.
GND
a. What is th?
b. What is the frequency?
c. What is the duty cycle?
d. List two ways you could change the components inthe above circuit to double the
frequency of the output pulses. Please demonstrate mathematically.

David · Accepted Answer

SOLUTION 
Sol1: -
From above logic circuit we have 
1)            
2)          
3)
X J K Q Q’ Y 
0 1 0 1 0 1 
1 1 1 0 1 0 
1 0 1 0 1 0 
0 1 0 1 0 1 
1 1 1 0 1 0 

Sol2: -
a) The above shown 555 timer circuit is in Astable mode with
In this mode the “High” time also known as “ON” time is given by  
        (     )    
Now, putting the given value in equation we get 
        (     )               
   
On evaluating we get
b) In this frequency of pulse is given by  
  
    
(      )   
 
Now, putting the given value in equation we get 
  
    
(           )            
 
On evaluating we get
Thus, frequency is
c) In this the duty cycle is given by 
           
   
        
 
This is given by  
           
(     )
(      )
 
Now, putting the given value in equation we get 
           
           
           
 
On evaluating we get
Thus, Duty cycle is given by
d) Consider the frequency of output pulse equation 
  
    
(      )   
 
Case 1:

FUll-Flop Characteristic Tables (a) JK Flip-Flop (b) SR Flip~Flop J K Q (t + 1) Operation S R Q(t+1} Operation 0 a Q(t) No change 0 0 •Q(t) No chanceD 0 1 a Reset 0 1 0 Reset 0 1 Set 1 0 1 Set Q(n...

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