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ConsidertransmissionofQPSKoveranarrowbandRayleighfadingchannelsuchthat, , where, isthechanneloutput, istheRayleighfading, yt Rt st nt y t R t ? ? ? ? ? ? istheQPSKsignal, and,...

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ConsidertransmissionofQPSKoveranarrowbandRayleighfadingchannelsuchthat, , where, isthechanneloutput, istheRayleighfading, yt Rt st nt y t R t ? ? ? ? ? ? istheQPSKsignal, and, isthezeromean,whiteGaussiannoisewithpowerspectraldensity Watts/Hz. Considerthecasewherethechannelfadingoverachannelisslowwith o s t N n t 2 ?? ?? ?? respecttoasymbolperiodand andtheRayleighfadingcanbeconsideredtobeconstantoverthesymbolperiod.Then,duringasymbol time, ,where, isaRay y t Rs t n t R ? ? leighrandomvaria ? ? ?? ?? ble. Ingeneral,hasaprobabilitydensityfunctiongivenof by, , , exp ,where, , . Thefadepameter modifiestheenvelopeofthesi R R r r r f r ur ur r R ? ? ? ? ? ? ?? ? ? ? ? ? ? ? ? XXXXXXXXXX ? ? ? ? ? ? ? ? gnal. Let = . hastheexponentialprobabilitydensityfunctiongivenby exp . Provethatfor ,then, , exp R a R f a ua E ER fr r ? ? ? ? ? ? ? ? ? ? ?? ? ? ? ? ? ? ? ? ? ? ? ? (i)(1mark XXXXXXXXXX2 1 2 ? ? ? ? ?? ? ? ? ? , exp , and,forconstant , = JustifywhyforaRayleighfadingchannelwithaverage theaveragebiterrorprobability b bb o oo b B o r ur f a aua E EE E N NN E P N ? ? ? ? ? ? ? ? ? ? (ii)(1mark) 2 isgivenby ,where istheaverageenergyperbitto ? ? one-sided noisedensityratioand istheenergyperbittoone-sidednoisedensity b b B o o b o E E P Q a f a da N N E N ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? 0 2 ?? ? ? ? ? ratio and isanexponentiallydistributedrandomvariablewithprobabilitydensityfunction givenby exp .
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ELEC426, Autumn, 2017, Assignment 4, Due:   8 June 2017                     Page 2    Q1 (5 marks total= XXXXXXXXXX) Consider transmission of QPSK over a narrowband Rayleigh fading channel such that,           yt?? R t s t n t , ?? ?? ? ? ?? where,        yt  is the channel output, ??                     Rt  is the Rayleigh fading, ??                     st  is the QPSK signal, ?? N o and,             nt ??  is the zero mean, white Gaussian noise with power spectral density   Watts/Hz. 2 Consider the case where the channel fading over a channel is slow with respect to a symbol period and and the Rayleigh fading can be considered to be constant over the symbol period.  Then, during a symbol time,              yt?? Rs t n t ,   where, R is a Rayleigh random variable. ? ? ?? ?? In  general, has a probability density function given of R by, 2 ???10 ,        r? , rr             fr?? exp ur ,      where,   ur? ?? ?? ?? ??? R 22 00 ,         r? . ??2 ??? The fade pameter R modifies the envelope of the signal. 1a ?? 2 Let ?? =Rf .       has the exponential probability density function given by a?? expua . ?? ?? ? 22 ?? 22 ?? ?? (i)    (1 mark)     1 2       Prove that for  ?? ,  then, 2 2       EE??? ??R1, ?? ??        2         fr??2r exp rur , ?? ?? ?? R         fa?? exp aua , ?? ? ? ?? ? EE??E bb b        and,  for constant  ,    E? =  ?? NN N oo ??o (ii)     (1 mark) E b        Justify why for a Rayleigh fading channel with average    the average bit error probability P B N o ? ?? ?? 2EE bb         is given by   PQ? afada,  where   is the average energy per bit to one-sided ?? ?? ?? B? ? ?? NN 0oo ?? ?? ??E b         noise density ratio and ?  is the energy per bit to one-sided noise density ratio  ?? N ??o         and ?  is an exponentially distributed random variable with probability density function         given by fa?? exp aua . ?? ? ? ?? ?ELEC426, Autumn, 2017, Assignment 4, Due:   8 June 2017                     Page 3    .  (iii)  (1 Mark)  EE bb Let ????...

Answered Same Day Dec 26, 2021

Solution

Robert answered on Dec 26 2021
119 Votes
Assignment 4
ELEC426, Autumn, 2017
Type Your Name Here
Date of Submission
Question 1
Given that, QPSK signal is transmitted over na
ow band,
y(t) = R(t)s(t) + n(t)
y(t) is channel output
s(t) is QPSK signal
n(t) is zero mean
R(t) is Rayleigh fading
Probability density function is given as,
( )





-----1
And the fade parameter is R
If, where is exponential probability density function,
( )





-------2
Where u[r] = 1 for r and 0 for r
(i) Now for



Equation 1 and 2 will become,
( )

( )
...
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