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Robert · Accepted Answer

Question Help 1 
 
 
 
 
1a)Load acting on the slab=0.15*25=3.75 kN/m2 (assuming f’c=N25) 
Load that comes on BC is half from the adjacent slabs 
=3.75*6 
=22.5 kN/m 
 
Load that comes on CF is half from the adjacent slabs 
=3.75*6 
=22.5 kN/m 
 
 
Load that comes on DE is half from the adjacent slabs 
=3.75*6 
=22.5 kN/m 
 
 
b) 
 
Total Load on the upper slab= 
3.75*8*24 
=720 kN 
 
Total Load on the Lower slab= 
3.75*17*24 
=1530 KN 
 
As the columns are equally spaced will take equal amount of load. 
 
AB will take=1530/10 
=153 kN i.e one-tenth of the total load in the lower slab as there are 10 columns.

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