Compute the corrected distance and its error with data given with attached file.Given the following...

Question

Compute the corrected distance and its error with data given with attached file.
Given the following tape calibration data:
C=(I -
LC,. = k(T —T)L
2 T 3 L C =w P, —P) A c E 24P2
A = 0.006 in2, 1 = XXXXXXXXXXft., l'= 100 ft., w= 0.02 lb. k= XXXXXXXXXX/°F, E = 29,000,000 lb/in2, P = 10 lb, T = 68°F
Compute the corrected distance and its expected error if the measured distance is XXXXXXXXXXft. Assume that Tf = 50°F ± 5°F, Pf= 20 lb ± 4 lb, a reading error of 0.005 ft., and that the distance was measured as two end-support distances of 80.00 ft. and 65.67 ft.

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Robert · Accepted Answer

Solution  
Correction for length can be calculated as 
CL = 0.006 ft x 145.67 ft / 100ft  = -0.

Compute the corrected distance and its error with data given with attached file. Given the following tape calibration data: C=(I - LC,. = k(T —T)L 2 T 3 L C =w P, —P) A c E 24P2 A = 0.006 in2, 1 =...

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