An industrial load operates at 30kW, 0.8 pf lagging. The load voltage is 240

Question

David · Accepted Answer

Consider figure 1
Consider the expression for load current rmsI  
 rms rms
P
I
V pf
   
Substitute 30Kw for P, 0.8 for pf and 240Vrms for Vrms 
30
240 0.8
30
192
156.25
rmsI
Arms




  
Therefore, the magnitude value of the load current is 156.25 A rms 
Consider the expression for the power factor angle 
  1cos pf    
Substitute 0.8 for pf 
 
 1cos 0.8
36.87
 



  
Therefore, the power factor angle at the load is 36.

An industrial load operates at 30kW, 0.8 pf lagging. The load voltage is 240

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