Reaction engineering problem- Question 7 – A rocket engine burns a stoichiometric mixture of fuel ( liquid hydrogen ) in oxidant ( liquid oxygen) . The combustion chamber is cylindrical , 75 cm long and 60 cm in diameter , and the combustion process produces XXXXXXXXXXkg/s of exhaust gases . if combustion is complete, find the rate of reaction of hydrogen and of oxygen. Solution - We want to evaluate - (-Rh2 = -rh2 ) =1/V*dNh2/dt And , - ro2 =1/V* d No2/dt Let us evaluate terms. The reactor volume and the volume in which reaction takes place are identical thus- V = ?/4 * ( 60/100)^2(75/100 ) = 0.79 *( 0.6)^2*(0.75)= XXXXXXXXXXm2 The reaction - H2 + ½ O2 ----?H20 Molecular weight H2 = 2 g O2 = 32 g ½ O2 =32/2 =16 g H2O = 18 g So, H2O PRODUCED /s = 108 /18 = 6 kg-mole /s H2 used = 6 k mols/s O2 usec = 3 kmol/s The rate of the reaction -rh2 = - 1/0.2121*6 = 2.829 *10^4 moles used/m3 of rocket –s -ro2 = -1/0.2121*3 =1.415 *10^4 moles /m3 -s
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