A message signal m(t) is normalized to peak voltages of +- 1V. The average power equals 20mW. To...

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A message signal m(t) is normalized to peak voltages of +- 1V. The average power equals 20mW. To transmit this signal by binary PCM without compression, uniform quantization is adopted. If the SQNR is required to be atleast 43dB, determine the minimum number of bits required to encode the uniform qu...

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Answer: 
Given that a message signal m(t) is normalized to peak voltages of 1 Volt  
The average power equals 20mW (milli Watts) 
 SQNR 43 dB decibels
 
 The minimum number of bits required to encode the uniform quantizer
 N ? Find  
 
 
 
q
q
SNR SQNR 43 dB
SNR 43 dB
1.

A message signal m(t) is normalized to peak voltages of +- 1V. The average power equals 20mW. To transmit this signal by binary PCM without compression, uniform quantization is adopted. If the SQNR is...

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