A domestic wastewater source has 1560 mg L-1 BOD, 82 mg L-1 total nitrogen (comprising Total...

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A domestic wastewater source has 1560 mg L-1 BOD, 82 mg L-1 total nitrogen (comprising Total Kjeldahl Nitrogen (TKN), nitrate and nitrite, and ammonia) and 15 mg L-1 soluble phosphorus (SP). These parameters need to be brought to

Yasodharan · Accepted Answer

Domestic Waste Water Source
In domestic waste water contains 99.9% water and 0.1% waste which we need to remove comprised of organic matter, microorganisms and inorganic compounds. There are major measures needs to be taken care of what is to be in treated water based on oxygen demand (BOD, COD), Indicator organisms (F.coli, E.coli etc.,) and Solid contents (TSS, TDS), in addition to this other measures to consider are ammonia & nitrate, total & reactive P, pH, alkalinity, odour and dissolved gases [1]. For the given parameter condition dissolved oxygen needs to be used after pre-treatment of wastewater to reduce down the organic carbons to energy, carbon dioxide, water and residue as expressed below,
Organic carbon + O2  Energy + CO2 + H2O + Residue
Nitrogen will be eliminated using nitrogen cycle scheme with the influence of microorganisms as most of the nitrogen present in water are released by protein degradation.
Organic – N + microorganisms  NH3/NH4+ [2]
And the phosphorous content is removed using chemical treatment at later stage using cations which gets easily bind to phosphate (Ca2+, Al3+, Fe3+)
The % removal based on given data is,
BOD % removal = (1560 – 30) / 1560 *100% = 98.07 %
TKN % removal = (82 – 15) / 82 *100% = 81.71%
SP % removal = (15 – 2.5) / 15 *100% = 83.

A domestic wastewater source has 1560 mg L-1 BOD, 82 mg L-1 total nitrogen (comprising Total Kjeldahl Nitrogen (TKN), nitrate and nitrite, and ammonia) and 15 mg L-1 soluble phosphorus (SP). These...

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