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A 2 mol% NH3-in-air mixture at 68°F and 1 atm is to be scrubbed with water in a tower packed with 1.5-in, ceramic Berl saddles. The inlet water mass velocity will be 2400 lbk-ft2, and the inlet gas...

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A 2 mol% NH3-in-air mixture at 68°F and 1 atm is to be scrubbed with water in a tower packed with 1.5-in, ceramic Berl saddles. The inlet water mass velocity will be 2400 lbk-ft2, and the inlet gas mass velocity 240 lb/h-ft2. Assume that the tower temperature remains constant at 68°F, at which the gas solubility relationship follows Henry's law, p = Hx, where p is the partial pressure of ammonia over the solution, x is the mole fraction of ammonia in the liquid, and His the Henry's law constant, equal to 2.7 atrnlmole fraction.
(a) Calculate the required packed height for absorption of 90% of the NH3.
(b) Calculate the minimum water mass velocity in lbk-ft2 for absorbing 98% of the NH3.
(c) The use of 1.5-in. ceramic Hiflow rings rather than the Berl saddles has been suggested. What changes would this cause in KGa, pressure drop, maximum liquid rate, KLa, column height, column diameter, HoG, and NoG
Answered Same Day Dec 31, 2021

Solution

David answered on Dec 31 2021
118 Votes
Id - 376240 –
Part -a
The mole of ammonia gas = 2 mol % = 2/100 =0.02
Air moles = 98 /100 =0.98
1.5 inch ceramic berl saddles rings -
Av = average bulk density l
ft3 of tower volume =38 l
ft3
Surface area av = 44 ft 2/ft3 ,porosity = e = 0.75
Gw = water mass velocity = 2400 lb /ft2 -hr
Gg = gas mass velocity = 240 l
ft2-hr
Temperature = 68 0 F and p=1 atm
Henry constant = H = 2.7 , P = H.X
The average molecular velocity of the entering gas mixture = 29 *98 /100 +2/100*17 = 28.7
l
mole
Ρy =ρy = density of gas = 28.7 *(460+32) /359*(468+68) = 0.0745 l
ft3
Ρx = ρx = 62.3 lb /ft3 , μ = viscosity = 1 cp
Gc = 4.17 *10^8 ft-lb /lb- hr2 , Gx /Gy = 1.0
For 1.5 in ceamic berl saddles –
Av = 44 ft2 /ft3 , e = 0.75
Gx /Gy *(ρy/ρx)^1/2 = (0.0745/62.3 )^1/2 = 0.0346
Gy ^2 ( μ’)^0.2 ( 62.3 /ρx)...
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