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TTs250712_Col34397_2
Question 1. Calculate the horizontal deflection at joint C. Use E=29,000 Ksi, I=1600
inches^4, A=700 inches^2 for all members
Support Reactions:
∑ FV = 0 gives RA + RD = 15×2 = 30
∑ MA = 0 RD × 15 – 15 × 2 × 7.5 = 0
Solving, RA = RD = 15 kg
Actual internal forces:
FAB = FCD = -15 kg (-ve due to compression)
Due to absence of horizontal reactions there are no bending moments in AB and CD.
MAB = 0 and MCD = 0
There would be no axial force in BC. FBC = 0
In BC, Mx = 15x – 2x2/2 =...