1. Find the area moment of inertia about the y axis for the shape shown. 30 points total3. The chest...

Question

1. Find the area moment of inertia about the y axis for the shape shown. 30 points total
3. The chest shown weighs 80 lbs with the location of the resultant chest weight located at G, which is supported under only part of the chest as shown. The surface coefficient of static friction is 0.4. Find the horizontal force P necessary to move the chest. State if the chest tips or slips during motion. 35 points
1. Find the force P that will cause the crate to be just on the verge of movement. (Hint: Consider Tipping vs. Slipping). The center of gravity of the crate is at the location G shown, the crate weighs 300 lbs, and the coefficient of static friction between the crate and the floor is ks XXXXXXXXXXpoints
Find the area moment of inertia with respect to the the x axis for the C-Chanel which is approximated by the shape shown below (35 points): „T
Example Problem
The crate has a ?leight of 200 lbs and a center of gravity at G as shown. Find the height h of the tow rope so that the crate slips and tips at the same time. What horizontal force P is required to do this? Take ils=0.4.

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David · Accepted Answer

Solution 
Position of center of Gravity of the rods along X-axis = 2.25’’ 
Moments of Inertia about X-axis = M.O.I of two rods along X-axis + M.O.I of rod along Y-Axis 
M.O.I of rods along X-axis can be calculated from parallel axis theorem 
= 2 {1/12 x 0.5 x 43 + (4 x 0.5) x 2.52}  
= 58.33in4 
M.O.I of rod perpendicular to X-axis can be calculated as 
= 1/3 x 5 x 0.53 = 0.208in4 
Hence 
Ix = 58.33 in4 (Answer)
Solution 
Moment of Inertia about Y- Axis = M.O.I of square about Y axis + M.O.I of Triangle about Y-Axis – M.O.I of semicircular 
portion about Y-Axis 
Position of center of gravity of Rectanglar portion = 17in 
Position of center of gravity of Rectanglar portion = 18in 
Position of center of gravity of Rectanglar portion = 18.66in 
Now moment of inertia of each geometrical section can be calculated using Parallel axis theorem  
Iy(Rectangular) = 
??ℎ3
12
 + bh x hcg2 = 
10 ??

1. Find the area moment of inertia about the y axis for the shape shown. 30 points total 3. The chest shown weighs 80 lbs with the location of the resultant chest weight located at G, which is...

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