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When raised to very high temperatures, many conventional liquid fuels dissociate into hydrogen and other components. Thus the advantage of a solid oxide fuel cell is that such a device can internally...

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When raised to very high temperatures, many conventional liquid fuels dissociate into hydrogen and other components. Thus the advantage of a solid oxide fuel cell is that such a device can internally reform readily available liquid fuels into hydrogen that can then be used to produce electrical power in a manner similar to Example 1.5. Consider a portable solid oxide fuel cell, operating at a temperature of Tfc = 800°C. The fuel cell is housed within a cylindrical canister of diameter D = 75 mm and length L = 120 mm. The outer surface of the canister is insulated with a low-thermal-conductivity material. For a particular application, it is desired that the thermal signature of the canister be small, to avoid its detection by infrared sensors. The degree to which the canister can be detected with an infrared sensor may be estimated by equating the radiation heat flux emitted from the exterior surface of the canister (Equation 1.5;  to the heat flux emitted from an equivalent black surface,  If the equivalent black surface temperature Tb is near the surroundings temperature, the thermal signature of the canister is too small to be detected—the canister is indistinguishable from the surroundings.

(a) Determine the required thickness of insulation to be applied to the cylindrical wall of the canister to ensure that the canister does not become highly visible to an infrared sensor (i.e., Tb - Tsur εs = 0.90) and (ii) the outer surface is comprised of a very thin polished aluminum sheet (εs = XXXXXXXXXXCalculate the required thicknesses for two types of insulating material, calcium silicate (k = 0.09 W/m ∙ K) and aerogel (k = 0.006 W/m ∙ K). The temperatures of the surroundings and the ambient are Tsur = 300 K and T∞ = 298 K, respectively. The outer surface is characterized by a convective heat transfer coefficient of h = 12 W/m2 ∙

(b) Calculate the outer surface temperature of the canister for the four cases (high and low thermal conductivity; high and low surface emissivity).

(c) Calculate the heat loss from the cylindrical walls of the canister for the four cases.

 

Answered 132 days After May 13, 2022

Solution

Dr Shweta answered on Sep 22 2022
64 Votes
Solution
Given: Portable solid oxide fuel cell, operating at a temperature of Tfc = 800°C or 1073 K, dimensions of cylinder = diameter D = 75 mm or 0.75 m, radius = 37.5 mm or 0.0375 m and length l = 120 mm or 0.120 m, heat flux emitted from an equivalent black surface, Eb = σTb4, Tb - Tsur < 5 K, εs = 0.90 for thin layer of dirt, εs = 0.08 for thin aluminum sheet, Tsur = 300 K and T∞ = 298 K, h = 12 W/m2, calcium silicate (k = 0.09 W/m ∙ K) and aerogel (k = 0.006 W/m ∙ K), Tb = 305 K.
To calculate: required thickness of insulation, outer surface temperature of the canister and heat loss from the cylindrical walls
Solution:
Part A: Calculation of required thickness of insulation to be applied to the cylindrical wall of the canister -
Firstly, we calculate the maximum allowable surface temperature as shown below:
Ts = [Tb4/Es]1/4-------[1]
Putting value of Tb = 305 K and εs = 0.90 for thin layer of dirt we get,
Ts1 = [3054/0.9]1/4 = 573.5K
And Putting value of Tb = 305 K and εs = 0.08 for thin aluminum sheet we get,
Ts2 = [3054/0.08]1/4 = 313.1 K
Now, hr is calculated as shown below:
hr = Es σ [Ts + Tsu
] [Ts2 +...
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