Verify the temperature distribution for case 2 in Sec. 2-9, i.e., that ...

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Verify the temperature distribution for case 2 in Sec. 2-9, i.e., that                     Subsequently show that the heat transfer is

David · Accepted Answer

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1. is n is of a nite length; it looses heat by conduction till end and then by convection
from end to the surrounding uid. erefore, the boundary conditions are as follows.
At x=0,
θ = θ0 = T0 −T∞,
At x=L,
−kAdT
dX
= −kAdθ
dX
= hAθ
e general solution is,
θ = C1e
−mx +C2e
mx
Diferentiating, we get,

Verify the temperature distribution for case 2 in Sec. 2-9, i.e., that Subsequently show that the heat transfer is

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