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Use the Laplace transform to solve the following differential equations: 1. y'+6y=2*t+3, y(0)=1 2. y'-2*y=exp(-t)*cos(t) , y(0)=-2 3. y''-y=2*t , y(0)=0, y'(0)=-1

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Use the Laplace transform to solve the following differential equations:
1. y'+6y=2*t+3, y(0)=1
2. y'-2*y=exp(-t)*cos(t) , y(0)=-2
3. y''-y=2*t , y(0)=0, y'(0)=-1
Answered Same Day Dec 26, 2021

Solution

David answered on Dec 26 2021
129 Votes
Ans. 1

The given differential equation,
( ) 6 2 3
d
y y t
dt
  
The above equation is of first order differential equation,
Its standard form is as,
' ( ) ( ) ( )y x p x y q x 
The general solution of the above equation is,
( )
( )
( )
( )
p x dx
p x dx
e q x dx C
y x
e
 




In the given equation compare it to the standard form,
( ) 6, ( ) 2 3p x q x t  
The integrating factor,
( )
6
p x t
t
I e
I e



Now,
6 ( ) 2 3
d
y y t
dt
  
Multiply 6te in the above equation on both side,
6 6 6 6.6 ( ) .2 .3t t t t
d
e y e y e t e
dt
  
By the integration by parts,
6 6 6( ) .2 .3t t t
d
e y e t e
dt
 
Now,
Solve the L.H.S.
6 6 6
6 6 6
6 6 6 6
1
( ) .2 .3
.2...
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