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Two-Variable Inequalities Read the following instructions in order to complete this assignment: Solve problem 68 on page 539 of Elementary and Intermediate Algebra, and make sure to study the given...

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Two-Variable Inequalities

Read the following instructions in order to complete this assignment:
  1. Solve problem 68 on page 539 of Elementary and Intermediate Algebra, and make sure to study the given graph. For the purposes of the assignment, it would be helpful to copy the graph onto your own scratch paper.
  2. Write a two to three page paper that is formatted in APA style and according to theMath Writing Guide. Format your math work as shown in theexampleand be concise in your reasoning. In the body of your essay, please make sure to include:
    • An answer to the three questions asked about given real-world situation.
    • An application of the given situation to the following two scenarios:
      • The Burbank Buy More store is going to make an order which will include at most 60 refrigerators. What is the maximum number of TVs which could also be delivered on the same 18-wheeler? Describe the restrictions this would add to the existing graph.
      • The next day, the Burbank Buy More decides they will have a television sale so they change their order to include at least 200 TVs. What is the maximum number of refrigerators which could also be delivered in the same truck? Describe the restrictions this would add to the original graph.
  3. An incorporation of the following math vocabulary words into your discussion. Use bold font to emphasize the words in your writing (Do not write definitions for the words; use them appropriately in sentences describing your math work.):
    • Solid line
    • Dashed line
    • Parallel
    • Linear inequality
    • Test point
Answered Same Day Dec 29, 2021

Solution

David answered on Dec 29 2021
107 Votes
The graph shows an inequality with 2 variables Refrigerator and TV.
To solve the inequality lets assume the number of TV’s be x and the number of Refrigerators be y.
Now solving for the eqn of the straight line y-0 = 330/-110(x-110) = y + 3x = 330
But, we have to take the entire region within the triangle, so the required inequality would be
y+3x <= 330
> With 71 refrigerators and 118 TV’s we get the value of y + 3x = 118 + 71 * 3 = 331 (Which is beyond
the capacity)
c > With 51 refrigerators and 176 TV’s we get the value of y + 3x = 176 + 51* 3 = 329 (Which is within
the capacity)
Situations...
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