Two cars are at rest, facing each other, and 200 meters
apart.
-If car one accelerates
at 6.00m/s^2...

Question

Two cars are at rest, facing each other, and 200 meters
apart.
-If car one accelerates
at 6.00m/s^2 up to maximum speed of
30.0m/s and car 2 accelerates at 5.00m/s^2 up to a maximum speed of 35.0
m/s, how long does it take the cars to meet?

David · Accepted Answer

Let   t time is taken.
First Car: 
Initial velocity = 0, So from v= u +ft , final vel. =v1= f1.t   (f1=6 m/s^2) … (1) 
Second  Car: 
Initial velocity = 0, So from v= u +ft , final vel.=v2= f2.t     (f2=5 m/s^2)   … (2) 
From (1) and (2),  v1/6 = v2/5  or, v1= 1.2 v2 … (3)
Now from v^2= u^2 + 2.

Two cars are at rest, facing each other, and 200 meters apart. -If car one accelerates at 6.00m/s^2 up to maximum speed of 30.0m/s and car 2 accelerates at 5.00m/s^2 up to a maximum speed of 35.0 m/s,...

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