to achieve the lowest latency a message is split into 24 packets. every packet has 15 bytes of...

Question

to achieve the lowest latency a message is split into 24 packets. every packet has 15 bytes of header. there are 11 hops between the source and the destination. Assume all devices are store-and-forward and it takes 1 ns to transmit 1 byte of data. what is the size of the message?

Robert · Accepted Answer

The message has a size of 165 bytes (15 bytes multiplied by 11 hops).
The message's latency is 165 bytes divided by 24 packets, or 6.875 ns.
 
The message's latency is 6.875 ns plus 1 ns (for the store-and-forward devices), for a total of 7.875 ns.

to achieve the lowest latency a message is split into 24 packets. every packet has 15 bytes of header. there are 11 hops between the source and the destination. Assume all devices are...

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