This problem has to do with liquids composed of two distinct substances in different...

Question

This problem has to do with liquids composed of two distinct substances in different proportions.

Considering that we have 100ml of each of the following liquids:
- Liquid 'Type 1' with 70% of Sub-A and 30% of Sub-B.
- Liquid 'Type 2' with 20% of Sub-A and 80% of Sub-B.

How many milliliters of each of the previous liquids we have to mix to obtain a liquid of 100ml with the following configuration:
- Liquid 'Type 3' with 50% of Sub-A and 50% of Sub-B.

Thank you for your help!

Pooja · Accepted Answer

let X be required ml of liquid 1 to be mixed in liquid 3
And Y be required ml of liquid 2 to be mixed in liquid 3
That is X+Y=1 ...(1)
Since i need 50% of substance A and 50% of substance B;
.7X + .2Y = .5
7X + 2Y = 5 ..

This problem has to do with liquids composed of two distinct substances in different proportions. Considering that we have 100ml of each of the following liquids: - Liquid 'Type 1' with 70% of Sub-A...

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