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Test 3 SU3 Math 131 Name: Test 3 Total Points: 53 INSTRUCTIONS: Show all your work and good luck. Use the Genius Scan app to scan your completed test, then submit the pdf under the Assignments tab in...

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Test 3 SU3
Math 131                              Name:
Test 3                                   Total Points: 53
INSTRUCTIONS: Show all your work and good luck. Use the Genius Scan app to scan your completed test,
then submit the pdf under the Assignments tab in Canvas by 11:59pm on Thursday, August 6th. Round all
solutions to the hundredths place. You must use the techniques and notation used in the screencasts on
Canvas to answer the questions.


1. A stat teacher found that the actual time studying for the last test was normally distributed with a mean of
8.1 hours and a standard deviation of 2.2 hours. The teacher is concerned about the progress of the
students in the lowest 5% of these times and wants to develop a study plan. What is the study time she
should be looking for as the cut-off? (3pts)











2. The lengths of a comedy show at a local club is normally distributed with a mean of 72 minutes and a
standard deviation of 22.8 minutes. 


a. What is the likelihood that a randomly selected show lasted between 60 minutes and 80 minutes?
    (4pts)










. You randomly select 32 performances. What is the probability that their mean is between 60 minutes
     and 80 minutes? (4pts)












c. Compare your answer from part a. and b. What accounts for any differences? You may draw a
     graph if that helps XXXXXXXXXX2pts)




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3. Among college students, the average weekly salary for those who work in a work study program is $243
with a standard deviation of $34. What is the probability that the mean salary for a sample of 40 students
in the program is more than $250? (4pts)















4. The monthly utility bills in a certain city are normally distributed with a mean of $110 and a standard  
deviation of $15.
a. Draw an accurate sketch of the distribution of monthly utility bills. Be sure to label the mean, as well as
          the points one and two standard deviations away from the mean. (3pts)


















b. What’s the likelihood a randomly chosen customer pays less than $95? (3pts)

















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c. Suppose the city wants to penalize the top 10% of utility users for using ‘too much’ electricity by
          assessing an extra fee. At what bill price do residents start getting hit with the penalty? (3pts)

















5. The U.S. President’s approval rating is at 42% with a margin of e
or of 5%. Assume the level of
confidence for the poll is 95%. Explain precisely what this means statistically, referencing specific
numbers. (2pts)












6. In a random sample of 28 sports cars, the average annual fuel cost was $2,218 and the standard deviation
was $523. Construct a 90% confidence interval for . Assume the annual fuel costs are normally
distributed. Interpret your results. (5pts)



















µ
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7. The National Study of the Changing Work Force conducted an extensive survey of 2958 wage and
salaried workers on issues ranging from relationships with their bosses to household chores. The data
were gathered through hour-long telephone interviews with a nationally representative sample. In
esponse to the question “What does success mean to you?” 1392 responded, “Personal satisfaction
from doing a good job.” Let p be the population proportion of all wage and salaried workers who would
espond the same way to the stated question. Find a 99% confidence interval for p. Interpret your
esults. (5pts)
















8. If you were to increase the level of confidence while keeping everything else the same, would a
confidence interval shrink, get larger, or stay the same? Explain. (2pts)











9. Pyramid Lake is on the Paiute Indian Reservation in Nevada. The lake is famous for cutthroat trout. The
Creel Survey reported that of a random sample of 51 fish caught, the mean length was 18.5 inches, with
standard deviation of 3.2 inches. Construct a 99% confidence interval for the mean length of fish in the
lake. Interpret your results. (5pts)















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10. The financial aid office at a local college needs information about student loans. They surveyed 16
andomly chosen students and collected some data. The mean loan amount for this sample was $2,286
with a standard deviation of $256. Assume the debt amounts are normally distributed. Find a 90%
confidence interval for the population mean student debt. Interpret your results. (5pts)





















11. An admissions director wants to estimate the mean age of all students enrolled at a college. The
estimate must be within 1.5 years of the population mean. Assume the population of ages is normally
distributed. Determine the minimum required sample size to construct a 99% confidence interval for the
population mean. Assume the population standard deviation is 1.2 years. (3pts)





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Answered Same Day Aug 07, 2021

Solution

Rajeswari answered on Aug 08 2021
151 Votes
63063 assignment
1) Let X be the actual time studying for the last test.
Given that X is N(8.1,2.2)
P(XUsing normal table we get c = 4.4813
So cut off time is 4.4813 hours
2) Let length of comedy show at local club be X
Given that X is N(72.22.8)
a) Reqd prob = P(60= 0.46505-0.299934 = 0.165715
) Here sample size = 32 so std dev now for sample = =4.031
P(60= F(70)-F(60) with std dev new
= 0.309893-0.001456=0.308437
c) Yes there is difference we get probability for sample higher than probability for individual. This is because std deviation changes which changes z value in std normal variate
Smaller one is for individual.
3) Let X be the average salary
X is N(243,34)
For samples of sizes 40 std deviation would be
Is x bar is N(243, 5.3758)
P(X bar >250) = 1-F(250) =1 -0.903561=0.096439
4) X=monthly utility bills in a certain city is N(110,15)
a) Graph is below
) P(X<95) = F(95) = 0.158655
c) P(X>c) = 10% i.e. F© = 0.90. Using Norm inv in excel we get c= 129.2233
So 129 units can be made as cut off for penalty for the top 10% users.
5)
The U.S. President’s approval rating is at 42% with a margin of e
or of 5%. Assume the level of confidence for the poll is 95%. Explain precisely what this means statistically, referencing specific numbers. (2pts)
Given that US approval rating is 42% = 0.42
i.e.p = proportion = 0.42
q = 1-p = 0.58
We know that proportion follows a normal distribution with mean = p = 0.42 and std dev =
Since margin of e
or is 5% = 0.05 we can say that we are 95% confident that for proportions of large random samples would be within...
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