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Microsoft Word - homework7 STAT 462 Homework 7 due Thursday, November 1, 2012 1. A pdf is defined by ( 2 ) if 0 )P X Y if X and Y are jointly distributed with pdf , ( , ) = , 0 1, 0 1.X Yf x y x y x...

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Microsoft Word - homework7
STAT 462

Homework 7
due Thursday, November 1, 2012

1. A pdf is defined by

( 2 ) if 0 < < 1 and 0 < < 2
( , ) =
0 otherwise
C x y y x
f x y





(a) Find the value of C .
(b) Find the marginal distribution of X .
(c) Find the joint cdf of X and Y . Define for all . 

2. (a) Find ( > )P X Y if X and Y are jointly distributed with pdf

, ( , ) = , 0 1, 0 1.X Yf x y x y x y    

(b) Find 2( < < )P X Y X if X and Y are jointly distributed with pdf

, ( , ) = 2 , 0 1, 0 1.X Yf x y x x y   

3. Define

2 2
,
21 0 < < < 1, 0
( , ) = 2
0
X Y
x y x y x
f x y
otherwise
 




Find the marginal distributions of X and Y .

4. Let 1Y and 2Y denote the proportion of time (out of one workday) during which employees I and II,
espectively, perform their assigned tasks. The joint relative frequency behavior of 1Y and 2Y is
modeled by the pdf


1 2
1 2 1 2
, 1 2
0 1, 0 1
( , ) = .
0Y Y
y y y y
f y y
otherwise
    




(a) Find  1 21 1, .2 4P Y Y 
(b) Find  1 2 1 .P Y Y 
(c) Find 1 2( 1/ 2 | 1/ 2)P Y Y  .
(d) Find the marginal probability density functions for 1Y and 2.Y
(e) Are 1Y and 2Y independent? Why or why not?
(f) Employee I has a higher productivity rating than Employee II and a measure of the total productivity
of the pair of employees is 30 1Y + 25 2Y . Find the expected value of this measure of productivity.
(g) Find the variance for the measure of productivity in (f).
5. The random variables X and Y have the joint distribution XYf given by


   
1 1
1 0,1,.... , 0 ,1
0, 0!
, .
0
x
y
XY
y x
x e
y
f x y
else
 
   
      
    

  





(a) Calculate the marginal pdf ( ).Xf x Identify this distribution and its parameter(s).
(b) Calculate the marginal pmf ( ).Yf y


• Book Problems: 5.15, 5.52, 5.59
Answered Same Day Dec 21, 2021

Solution

Robert answered on Dec 21 2021
127 Votes
*Note: in case of marginal distributions, the marginal pdf has been provided.
1.a)
From the definition of PDF we have ∫ ∫ ( )



∫ ( )


Hence,

∫ ( )
) Marginal distribution of X can easily be obtained by integrating the PDF over its support
along the y-component.
Marginal distribution of X : ( ) ∫ ( )


( )|
( )
c) Its clear from the definition that for or the CDF will be 0 and for the CDF
will be 1.
if and then ( )


( )
if and then ( ) (


)
if and then
( ) ∫ ∫ ( )

∫ ( )
( ) ( )
2.a)
The probability can easily be found out using the concept of conditional probability and then
integrating over all possible y (or x) values.
( √ ) ∫ ( √ ) ( )
∫ ( (√ )) ( )
∫ (





√ ) (

)
)
The probability can easily be found out using the concept of conditional probability and then
integrating over all possible y (or x) values.
( ) ∫ ( ) ( )
∫ ( ( ) (
)) ( )
∫ ( )( )
3.
Marginal...
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