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Australia McAllister, Ian, The Australian National University Makkai, Toni, The Australian National University Bean, Clive, Queensland University of Technology Gibson, Rachel Kay, University of...

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Australia
McAllister, Ian, The Australian National University
Makkai, Toni, The Australian National University
Bean, Clive, Queensland University of Technology
Gibson, Rachel Kay, University of Mancheste
Australian Election Study, 2016
Study Documentation
March 6, 2017
Metadata Production
Metadata Producer(s) Australian Data Archive (ADA) , The Australian National University
Version Version 1.0
Identification au.edu.anu.ada.ddi.01365
Table of Contents
Overview.......................................................................................................................................... XXXXXXXXXX4
Scope & Coverage........................................................................................................................... XXXXXXXXXX4
Producers & Sponsors..................................................................................................................... XXXXXXXXXX5
Sampling.......................................................................................................................................... XXXXXXXXXX5
Data Collection................................................................................................................................ XXXXXXXXXX5
Data Processing & Appraisal.......................................................................................................... XXXXXXXXXX6
Accessibility..................................................................................................................................... XXXXXXXXXX6
Rights & Disclaimer........................................................................................................................ XXXXXXXXXX6
Files Description.............................................................................................................................. XXXXXXXXXX7
au.edu.anu.ada.ddi.01365............................................................................................. XXXXXXXXXX7
Variables Group(s)........................................................................................................................... XXXXXXXXXX8
Administration Variables............................................................................................. XXXXXXXXXX8
Section A: The Election Campaign............................................................................ XXXXXXXXXX8
Section B: Party Preference and Voting................................................................... XXXXXXXXXX13
Section C: Politicians and Government.....................
Answered Same DayOct 15, 2021SOCY2339

Solution

Caleb answered on Oct 16 2021
59 Votes
Assignment 2: Making Inferences about Government Regulated Death and Dying
PART A: Manual Calculations
1. Z scores and the Area under the Normal Curve
a. Find the proportion of observations (area under the curve) from a standard
normal distribution that satisfies each of the following statements (1.5 marks):
i. Z > -0.63
Solution
From the standard normal distribution table, the proportion co
esponding to Z = -0.63 is 0.2644
Z > -0.63 = 1 – 0.2644 = 0.7356
ii. Z < 2.07
Solution
From the standard normal distribution table, the proportion co
esponding to Z = 2.07 is 0.9808
Z < 2.07 = 0.9808
iii. -1.23 From the standard normal distribution table, the proportion co
esponding to Z = -1.23 is 0.1094
The proportion co
esponding to Z = 1.46 is 0.9279
-1.23 . Find the value of the Z score that satisfies each of the following conditions (1
mark):
i. The value of Z with 25% of observations falling below it;
We need to determine the value of Z with a co
esponding proportion of 0.25. From the standard normal distribution table, the value of Z is -0.67
ii. The value of Z with 34% of observations falling above it.
Since 34% of observations are falling above it, 66% are falling below it. We need to determine the value of Z with a co
esponding proportion of 0.66. From the standard normal distribution table, the value of Z is 0.41
c. Suppose respondents in a survey were asked about how long they think a
terminally ill patient must wait after diagnosis before they should be allowed
to end their life with medical assistance (in months). The variable that
epresents waiting time (in months) from receiving their diagnosis to being
able to end their life with medical assistance has an approximate normal
distribution, with a mean of 18 months and a standard deviation of 6 months
(3 marks).
i. What proportion of patients would have to wait at least 24 months?
First we determine the value of Z.
Z = (x - µ) / σ = (24 – 18) / 6 = 6/6 = 1
The proportion co
esponding to Z = 1 is 0.8413. This is the proportion of patients who would wait at most 24 months. The proportion of patients who would wait at least 24 months is 1 – 0.8413 = 0.1587.
ii. What proportion of patients would have a waiting period take between
4 and 12 months?
We determine the Z values and proportions for both 4 months and 12 months.
Z = (4 – 18) / 6 = -2.33
The proportion co
esponding to a Z value of -2.33 is 0.0099
Z = (12 – 18) / 6 = -6 / 6 = -1
The proportion co
esponding to a Z value of -1 is 0.1587
The proportion of patients having a wating period between 4 and 12 months is 0.1587 – 0.0099 = 0.1488.
iii. What is the waiting time associated with 15% of patients falling below
it?
First, we determine the Z value co
esponding to a proportion of 15% or 0.15. From the standard normal distribution table, the value of Z co
esponding to a proportion of 0.15 is 1.04.
1.04 = (x – 18) / 6
X – 18 = 6 * 1.04
X = 18 + 6.24 = 24.24
d. The distribution of Australian voters with a relative who has been diagnosed with a terminal illness is skewed to the right, with a µ=1.6 and σ = 0.4. These values of the population are known to you as the researcher who takes a sample of voters from the population of Australian voters in order to estimate the mean number of relatives who have been diagnosed with a terminal illness for each...
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