Refer to the previous exercise and the solution to (b).

a. The sample proportion of...

Question

Refer to the previous exercise and the solution to (b). 

a. The sample proportion of malformations is much higher in
the highest alcohol category than the others because, although it has only one
malformation, its sample size is only 38. Is the result sensitive to this
single malformation observation? Re-fit the model without it (using 0
malformations in 37 observations at that level), and re-evaluate estimated
probabilities of malformation at alcohol levels 0 and 7 and the relative risk. 

b. Is the result sensitive to the choice of scores? Re-fit
the model using scores (0, 1, 2, 3, 4), and re-evaluate estimated probabilities
of malformation at the lowest and highest alcohol levels and the relative risk.


c. Fit a logistic regression or probit model. Report the
prediction equation. Interpret the sign of the estimated effect.

Amar Kumar · Accepted Answer

a) Yes, as the relative risk calculation shows, the outcome depends on the choice of scores. Use a linear probability model, similar to the re-fit model. Here, no method for fitting a linear probability model is presented.
b) Given: 
	Y= whether a child has an malformation sex organ
	X= mother’s alcohol consumption
We know regression equation is,
	Y=β0 + β1x + 
Where  ~ N (0, 62   )
From above output 
β0 = 0.00255 where β0= intercept &
β1=0.00109     where β1=slope.

Refer to the previous exercise and the solution to (b). a. The sample proportion of malformations is much higher in the highest alcohol category than the others because, although it has only one...

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