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Q1. An electron is bound in one dimensionalbox of size 50 pm. What will be the minimum energy? b) It is known that a classical point particle moves back and forth with constant speed between two walls...

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Q1.
An electron is bound in one dimensionalbox of size 50 pm. What will be the minimum energy?
b) It is known that a classical point particle moves back and
forth with constant speed between two walls at x =0 and x = 8.0 cm (as shown in the Figure-1). No additional information about the location of the particle is known.
(a) What is the probability of density P (x)?
(b) What is the probability of finding the particle at the point where x equals to exactly 2 cm?
(c) What is the probability of finding the particle between x = 3.0 cm and x= 3.4 cm?
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Q1. An electron is bound in one dimensionalbox of size 50 pm. What will be the minimum energy? b) It is known that a classical point particle moves back and forth with constant speed between two walls at x =0 and x = 8.0 cm (as shown in the Figure-1). No additional information about the location of the particle is known. (a) What is the probability of density P (x)? (b) What is the probability of finding the particle at the point where x equals to exactly 2 cm? (c) What is the probability of finding the particle between x = 3.0 cm and x= 3.4 cm?

Answered Same Day Dec 26, 2021

Solution

Robert answered on Dec 26 2021
97 Votes
Quantum Mechanics Solution
1) The energy of an electron En = n
2h2/8mL2
It’s being asked to calculate minimum energy, so we will take the ground state, i.e. n=1
So energy = h2/8mL2
L = 50 pm = 50*10-12 m
h= 6.63*10-34
m = mass of electron = 9.1*10-31
Energy E = {6.63*10-34)2/...
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