Prove Proposition III-46: Under the same assumptions as in III-45. angle ACF – angle DCG and angle CDF – angle BDG (Fig.4.34).

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Prove Proposition III-46: Under the same assumptions as in III-45. angle ACF – angle DCG and angle CDF – angle BDG (Fig.4.34).

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Prove Proposition III-46: Under the same assumptions as in III-45. angle ACF =angle DCG and angle CDF =angle BDG (Fig.4.34).
Solution:
Consider bigger circle EHFC:
Chord EH is common for both the angle ECH and angle EFH.

Prove Proposition III-46: Under the same assumptions as in III-45. angle ACF – angle DCG and angle CDF – angle BDG (Fig.4.34).

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