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Please refer to the attached file, for the drawing and question regarding this problem. Please do not hesistate to reply if any unclarified issues are encountered or any missing values that are...

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Please refer to the attached file, for the drawing and question regarding this problem. Please do not hesistate to reply if any unclarified issues are encountered or any missing values that are important to take into consideration. Thanks
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Answered Same Day Dec 22, 2021

Solution

David answered on Dec 22 2021
119 Votes
SOLUTION-
Given data
Length of roller, L = 1500 mm = 1.5 M
Mass of roller, M = 15 Kg
Radius of roller, R= 75 mm = 0.075 M
Speed of roller, VR = 18 m/s
Work piece size = 1500 x1500x25 (mm)
∆h= a= 0.1 mm
Speed of work piece, VO = 7.5 m/s
PR = Radial force
F= Tangential frictional force
FH= Horizontal component of Tangential frictional force
FH= F Cos α
Horizontal component of Radial force = PR Sin α
Work piece will be drawn if
F Cos α > PR Sin α
R
a
= 25 mm PR
F
α
F= μ PR
μ = F/ PR
μ = Tan α
Where μ = frictional co-efficient
(LP)
2 = R2 – (R-a) 2
LP= √ (2Ra)
Tan α = LP / (R-a)
Tan α = √ (2Ra) / (R-a)
Tan α = √ (2a/R)
Now we will...
SOLUTION.PDF
SOLUTION.PDF

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