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Multivariable calculus problems

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This is the fourth midterm exam for Math 210.
It consists of 15 questions, for a total of 75 points. You will have 75 minutes to complete it.
Show all your work in the provided white-space under each problem and clearly indicate your answer.
Partial credit may be given generously, even for wrong answers, if you demonstrate understanding of what
your instructor has taught you. A wrong answer with no work shown earns zero points. A right answe
with no work shown is suspicious.
By taking this exam you agree to respect Chapman University’s policies concerning academic honesty. In
particular, you will not copy from others during this exam and will not communicate exam topics with
anyone until all exams are collected. You may only use a basic scientific calculator, no cell phones o
computers, or notes of any kind are permitted.
Please read each question carefully and follow instructions. If you finish early, double check all of you
solutions for completeness and co
ectness.
Page: XXXXXXXXXXTotal
Points: XXXXXXXXXX10 75
Score:
This page has been left blank. Feel free to use it as scratch paper.
1. (5 points) Compute∫
γ
xyds
where γ is the straight line segment connecting (1, 1) to (2, 3).
2. (5 points) Compute∫
γ
F⃗ · T⃗ ds
where F⃗ = ⟨−y, x, z⟩ and γ is the helix
γ = ⟨cos(t), sin(t), t⟩
0 ≤ t ≤ π
3. (5 points) Show that the vector field
F⃗ = ⟨−y2, x2⟩
is not conservative.
4. (5 points) The vector field
F⃗ = ⟨yz + 2xz2 + y, 2yz + x+ xz, y2 + 2x2z + xy⟩
is conservative. Find a function f such that
∇f = F⃗
5. (5 points) For the vector field
F⃗ =
x⃗i+ yj⃗√
x2 + y2
compute∫
γ
F⃗ · T⃗ ds
along the curve
x = (1 +
t
Ï€
) cos(t2 + (1− 2π)t)
y =
2t
Ï€
+ sin(t)
0 ≤ t ≤ 2π
Work smarter, not harder. This is easy if you approach it with the right theorem.
6. (5 points) Find the area of the region enclosed by the curve
x = t(t− 2)et
y = t2(t− 2)et
0 ≤ t ≤ 2
7. (5 points) Consider the annulus Ω of all points 1 ≤ x2 + y2 ≤ 4 and the vector field
F⃗ = ⟨x sin
(Ï€
6
(
x2 + y2 − 1
))
, y sin
(Ï€
6
(
x2 + y2 − 1
))
⟩
Compute∫∫
Ω
div(F⃗ )dA
Again: work smarter, not harder.
8. (5 points) Find the surface area of the helicoid
⟨u cos(v), u sin(v), v⟩
0 ≤ u ≤ 1, 0 ≤ v ≤ 2π
9. (5 points) Let Σ be the helicoid as in the previous question. Compute the surface integral∫∫
Σ
√
x2 + y2dA
10. (5 points) Let Σ be the part of the paraboloid z = 9− x2 − y2 where z ≥ 0. Compute the flux integral
across Σ of
F⃗ = ⟨x, y, z⟩,
using the upward pointing unit normal to Σ.
11. (5 points) An easier problem: Compute the curl of the vector field
F⃗ = ⟨x2 + yz, y2 + xz, z2 + xy⟩.
Is F⃗ conservative?
Stokes’ Theorem Stuff
12. (5 points) Suppose Σ is an oriented surface in space with two disjoint boundary curves γ1 and γ2 which
are oriented positively with respect to Σ. If F⃗ is a vector field where∫
γ1
F⃗ · Tds = 2
and ∫
γ2
F⃗ · Tds = 5,
what is the value of∫∫
Σ
curl(F⃗ ) · ndA?
13. (5 points) In electromagnetism, if E⃗ is a constant in time electric field and B⃗ is the magnetic field, then
curl(B⃗) =
4Ï€
c
J⃗
where c is some constant (the speed of light) and J⃗ is the cu
ent density field, meaning the cu
ent
passing through a surface is the flux integral∫∫
Σ
J⃗ · dA⃗
Supposing that the magnetic field is conservative in a region Ω where the electric field is constant in
time, how much cu
ent passes through any surface in the region?
Divergence Theorem Stuff
14. (5 points) Use the divergence theorem to compute the integral∫∫∫
Ω
x2dV
where Ω is the inside of the torus
x = cos(u)
y = (sin(u) + 2) cos(v)
z = (sin(u) + 2) sin(v)
0 ≤ u ≤ 2π, 0 ≤ v ≤ 2π
15. (5 points) Compute the flux integral of
F⃗ = ⟨yz, x sin(z2), x2⟩
across the hemisphere x2 + y2 + z2 = 1, z ≥ 0, with upward pointing unit normal.
Clever use of the divergence theorem can save you a lot of work. Think about capping off this hemisphere.
Answered Same Day May 11, 2022

Solution

Rajeswari answered on May 12 2022
92 Votes
105578 assignment
12
Q.no1
The curve here is a line passing through (1,1) and (2,3)
Equation is y = 2x-1
Xy = x(2x-1) = 2x^2 –x
Ds = dx (projecting on the x axis)
Reqd integral =
Q.no2
Given that r = cost I +sint j +tk
Del r = -sint I +cost j +k
||delr || =
T = unit normal = del
||del r||
F.T =
Also ds = dxdy
Hence required integral =
Qno.3
Given that F =
i.e. F is of the form (P,Q)
Since the above two are not equal we get the Vector field is not conservative
Q.no.4
Given that F =
Is conservative.
We have to find f such that del f = F
Let us integrate first component with respect to x
Note that here we use for constant term a function of y and z since we ingegrated with respect to x only.
Then f =
Hence g’(y,z) = 2yz
Integrate wrt y and make constant a function of z
i.e. f =
Partially differentiate wrt z
Equate this to 3rd component of F
i.e.
h’(z) =0 and hence h(z) = C
Function f =
Qno.5
Div F =
= =0
Applying Gauss divergence theorem, the reqd integral =...
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