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MODULE TITLE : HEAT TRANSFER AND COMBUSTION TOPIC TITLE : HEAT EXCHANGERS Document Preview: THIS BOX MUST BE COMPLETED Student Code No....

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MODULE TITLE : HEAT TRANSFER AND COMBUSTION TOPIC TITLE : HEAT EXCHANGERS
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THIS BOX MUST BE COMPLETED Student Code No. .................................................................................................... Student's Signature .................................................................................................. Date Submitted ........................................................................................................ Contact e-mail ......................................................................................................... MODULE TITLE : HEAT TRANSFER AND COMBUSTION TOPIC TITLE : HEAT EXCHANGERS TUTOR MARKED ASSIGNMENT 3 NAME........................................................................................................................................ ADDRESS ................................................................................................................................. ................................................................................................................................................... ................................................................................................................................................... ................................... XXXXXXXXXXHOME TELEPHONE ..................................................... EMPLOYER.............................................................................................................................. ................................................................................................................................................... ................................................................................................................................................... ................................... XXXXXXXXXXWORK TELEPHONE...................................................... HTC - 3 - TMA (v1) © Teesside University 2011Published by Teesside University Open Learning (Engineering) School of Science &...

Answered Same Day Dec 26, 2021

Solution

David answered on Dec 26 2021
132 Votes
1
a) Φ=qmc cpC (TC1-TC2) = qmH cpH (TH1-TH2)
Therefore: Φ = qmc cpC (TC1-TC2)
Φ = 0.050 x 4.184 x (85-16)
Φ = 0.209 x 69 Φ = 14.4W
Now:
14.4 =0.044 x 1.075 x (410 - TH2)
14.4/0.044 x 1.075 = (410 - TH2)
= 410 – 304
TH2 = 106 degrees
) ̇
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c) ̇
d) TH1 = 420 degrees
TH2 = 106 degrees
TC1 = 16 degrees
TC2 = 85 degrees
2
a)






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( ...
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