Solution
Robert answered on
Dec 22 2021
2048-11
Sol :( I) Chebyshev’s inequality says that the probability,
P
of being further than
a
from the mean,
m
is limited by:
(
)
2
2
Px
s
ma
a
-³£
Where
s
2
the variance for our case, 292 and 162 is are both 65 from the mean of 227, so
(
)
2
22
1311
654%
25
655
Px
m
-³£===
Now, if 4% fall outside this range,
96%
must fall inside.
Sol​ :( II) The empirical rule says that 99.7% of the data fall within 3 standard deviations of the mean. The 3-sigma values for our distribution are
(
)
246316198 and 294,
±´=
So 99.7% of the data fall between 198 and 294.
Sol: (2) Nine college students had eaten the following number of times at a fast food restaurant for the dinner in the last ten days:
10, 10, 2, 4, 7, 0, 7, 4, 3
The mean represents the average or the sum of the data divided by the number of pieces of data:
10+10+2+4+7+0+7+4+3
Mean,
9
47
Mean,
9
Mean5.23,
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=
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=
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=
The median is the value in the middle of a set of ranked data.
Firstly a
ange the data in ascending order.
0, 2, 3, 4, 4, 7, 7, 10, 10
Median
4,
=
Mode- Count the number of times each data value occurs. The one that occur the most often is the mode. If more than one value occurs most often, the distribution is multi-modal two mode values: bimodal, three is called trimodal.
Mode
4,7,10
=
Because the number 4, 7 and 10...