Extracted text: L A ball is attached to a spring, which is stretched and then let go. The height of...

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Extracted text: L A ball is attached to a spring, which is stretched and then let go. The height of the ball is given by the sinusoidal equation y = -2.5cos(t) +6
%3D
where y is the height above the ground in feet andtis the number of seconds since the ball was released. How long, to the nearest tenth of a
second, does it take for the ball to return to its starting height?
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Rajeswari · Accepted Answer

112894 assignment
Initially i.e. at the start t=0
When t=0 height is given by
Y=-2.5  where t=0
Substitute t =0 .  We know cos 0 = 1
Hence initial height 
Y = -2.5+6 = 3.5 feet
The same height it would reach when again 
3.5 =-2.

L A ball is attached to a spring, which is stretched and then let go. The height of the ball is given by the sinusoidal equation y = -2.5cos(t) +6 %3D where y is the height above the ground in feet...

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