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KINE-1800_Assignment 4_F21 © 2021 – Dr. Nadia Azar 1 KINE-1800 Fundamental Mechanics of Human Movement ASSIGNMENT #4 6% of Final Grade DUE by 4:00 PM on Friday, November 19, 2021 Total out of 19...

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KINE-1800_Assignment 4_F21
© 2021 – Dr. Nadia Azar 1
KINE-1800 Fundamental Mechanics of Human Movement
ASSIGNMENT #4
6% of Final Grade
DUE by 4:00 PM on Friday, November 19, 2021
Total out of 19 Marks: _________________________
Name: ________________________________________
Student ID#: __________________________________
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© 2021 – Dr. Nadia Azar 2
Question 1 [4 marks]. During a flip, a gymnast can manipulate their angular velocity even though no
external moments are applied to their body. For example, their angular velocity as they land is much
less than their angular velocity during the tuck portion of the flip. Which mechanical property does
the gymnast purposefully manipulate to decrease their angular velocity as they land, and how do
they do it?














Question 2 [4 marks]. Based what you know about the factors that contribute to an object’s
stability, explain why an elderly person might have more difficulty getting up out of a low, deep
chair than getting up out of a standard-height chair?














© 2021 – Dr. Nadia Azar 3
Question 3 [4 marks]. A person performs a bent-over lateral cable raise and
hold the position shown in the image to the right (assume the upper limb is
fully extended and parallel to the ground). A free-body diagram of the
forces acting on the upper arm and their moment arms has been provided.
i. What is the magnitude and direction of the net moment caused by
the weight of the upper arm (W) and the tension in the cable (T)?
ii. How much force must the deltoid muscle generate (FD) to hold the
upper arm stationary in this position?



























"File:Bent-over-cable-lateral-
aises-1.png" by Everkinetic is
licensed under CC BY-SA 3.0.
© 2021 – Dr. Nadia Azar 4
Question 4 [4 marks]. You start at t = 0 s with your knee fully extended (see figure), and then you
flex your knee until the lower leg stops when it is vertical at t = 4.0 s. The mass of the lower leg is
3.78 kg and its radius of gyration is 0.24 m. The angular position and velocity at t = 2.2 s are shown
in the figure.


i. Calculate the average angular impulse from t = 0 s through t = 1.23 s. [2 marks].
ii. Calculate the magnitude and direction of the net moment t = 0 s through t = 1.23 s. [1 mark]
iii. Using the angular analog to Newton’s 2nd Law, calculate the average angular acceleration of
the lower leg from t = 0 s through t = 1.23 s. [1 mark]



















t = 0 s
θ = 0 rad
ω = 0 rad/s
t = 1.23 s
θ = -0.79 rad
ω = -1.28 rad/s
t = 4.0 s
θ = -1.57 rad
ω = 0 rad/s
© 2021 – Dr. Nadia Azar 5
Question 5. [3 marks]. Give an example of a short answer question you think would make a great
question on an exam and provide the co
ect answer for it. This could be either a text/theory
question or a calculation.

Question = 1 mark, co
ect answer to the question = 2 marks
Answered 2 days After Nov 14, 2021

Solution

Ravindra Kumar answered on Nov 17 2021
123 Votes
Question 1
During a flip, a gymnast can manipulate their angular velocity even though no external moments are applied to their body. For example, their angular velocity as they land is much less than their angular velocity during the tuck portion of the flip. Which mechanical property does the gymnast purposefully manipulate to decrease their angular velocity as they land, and how do they do it?
Solution
During the flip, gymnast used to manipulate their angular velocity because we know that the angular momentum always be conserve if any external force is not getting apply on it.
Let the mass of the gymnast be m, initial moment of inertia be and let he is rotating with angular velocity then his initial angular momentum will be
But when he flipped his body then his moment of inertia gets change, then due to changing of the moment of inertia of the body, his angular velocity will also get change.
Applying the conservation of angular momentum
Here, new angular velocity of the body be and new moment of inertia of the body becomes .
So, we can conclude that gymnast is changing the moment of inertia of the body by opening his hand and legs, due to which angular velocity of the body is also getting change.
Question 2
Based what you know about the factors that contribute to an object’s stability, explain why an elderly person might have more difficulty getting up out of a low, deep chair than getting up out of a standard-height chair?
Solution
As we know that elderly person has the higher length (height) than the younger person. Due to which the centre of mass of the elder person used to be at bigger hight than the younger person’s height. So, when the elder person sit into the deep chair with respect to the normal standard chair his body’s centre of mass goes to much lower height. It means, elder person, when he was in standing position have higher potential energy.
Let initially his centre of mass be at height and...
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