Just need your help of the part 4 analysis, question of No2. and No.3 In this experiment, we...

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Just need your help of the part 4 analysis, question of No2. and No.3

In this experiment, we determined the relationship between the acceleration of a system of two masses and the total mass in this system when the net force remains constant. We kept the hanging mass constant by setting it to 0.2kg (m₁). Then we gradually increased the cart mass (m₂) and recorded the time it took the cart to move a fixed distance of 0.5m from rest. Finally, we calculated the acceleration using data of distance traveled andaverage time (L=V₀t+0.5at²) and make a graph of acceleration (a) vs. the reciprocal of total mass (1/M) to analyze our results.

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Robert · Accepted Answer

1. Graph
Slope = (1.42 – 0.86)/(3.33-2.032) = 0.43
From the graph, we can see that the horizontal intercept of the data occurs at a = 0.20m/s2
2. The weight of the hanging mass is 0.5kg and the slope is 0.43. Thus, there is a deviation of 0.5 – 0.43 = 0.07.
3. Since, there is a noticeable horizontal intercept, it is understood that as the mass of m2 becomes increasingly large, the acceleration no longer reduces but converges to a finite value.
Conclusion
If a constant force acts on a system of two masses,

Just need your help of the part 4 analysis, question of No2. and No.3 In this experiment, we determined the relationship between the acceleration of a system of two masses and the total mass in this...

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