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If necessary, they need to be done using Maple software or Microsoft Equation 3.0 Document Preview: Exercise #12) Show that [x]+ [x + 1/2]= [2x] whenever x is a real number. Exercise #22) Conjecture a...

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If necessary, they need to be done using Maple software or Microsoft Equation 3.0
Document Preview:

Exercise #12) Show that [x]+ [x + 1/2]= [2x] whenever x is a real number. Exercise #22) Conjecture a formula for the nth term of {an} if the first ten terms of this sequence are as follows: a) 3, 11, 19, 27, 35, 43, 51, 59, 67, 75 b) 5, 7, 11, 19, 35, 67, 131, 259, 515, 1027 c) 1, 0, 0, 1, 0, 0, 0, 0, 1, 0 d) 1, 3, 4, 7, 11, 18, 29, 47, 76, 123 Exercise #6) By putting together two triangular arrays, one with n rows and one with n - 1 rows, to form a square (as illustrated for n = 4), show that tn-1 + tn = n2, where tn is the nth triangular number. (it’s a 4 by 4 square with 16 dots in it)- fyi Exercise #10) Show that p1=1and pk=pk-1+(3k -2) for k =2. Conclude that XXXXXXXXXXpn= knk=1 (3k -2) and evaluate this sum to find a simple formula for pn. Exercise #18) Find n! for n equal to each of the first ten positive integers. Exercise #8) Use mathematical induction to prove that j=1n j3 = XXXXXXXXXXn3 = [n(n + 1)/2]² for every positive integer n. Exercise # 14) Show that any amount of postage that is an integer number of cents greater than 53 cents can be formed using just 7-cent and 10-cent stamps. Exercise # 20) Use mathematical induction to prove that 2n <>

Answered Same Day Dec 23, 2021

Solution

Robert answered on Dec 23 2021
134 Votes
1
Exercise 1.3 E)
Solution: For n = 1, the statement reduces to 1
2
=
6
321 
and is obviously true.
Assuming the statement is true for n = k:
1
2
+ 2
2
+ 3
2
+ . . . + k
2
=
6
)2)(1(  kkk

We will prove that the statement must be true for n = k + 1:
1
2
+ 2
2
+ 3
2
+ . . . + (k + 1)
2
=
6
)32)(2)(1(  kkk

The left-hand side of (2) can be written as
1
2
+ 2
2
+ 3
2
+ . . . + k
2
+ (k + 1)
2

In view of (1), this simplifies to:
(1
2
+ 2
2
+ 3
2
+ . . . + k
2
) + (k + 1)
2
= 2)1(
6
)2)(1(


k
kkk

=...
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