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I want the solutions of these questions ASAP.
Answered Same Day Dec 29, 2021

Solution

Robert answered on Dec 29 2021
106 Votes
3. (a) For the vector space V , we have suppose (x, y) ∈ V , then (ax, ay) ∈ V
for any a ∈ R.
Fo
V1 = {(x, y) : y ≤ 2x + 1}
We see (x, y) = (0,−6) ∈ V1, Hence if V1 is a vector space then
for a = −1, (ax, ay) = (−1 × 0,−1 × −6) should belong to V1.
But (ax, ay) = (0, 6) and this does not satisfy y ≤ 2x + 1. Hence
(0, 6) /∈ V1. Hence V1 is not a vector space.
Fo
V2 = {(x, y) : y > |x|}
We see (x, y) = (0, 1) ∈ V2, Hence if V2 is a vector space then fo
a = −1, (ax, ay) = (−1 × 0,−1 × 1) should belong to V2. But
(ax, ay) = (0,−1) and this does not satisfy y > |x|. Hence (0,−1) /∈
V2. Hence V2 is not a vector space.
(b) Given equation of plane can be written as
5x− 2y + 3z = 11
Take
l1 : 5x− 2y = 11, z =...
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