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I need to have an assignment done for discrete math, step by step detailed answers, especially for proofs.

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I need to have an assignment done for discrete math, step by step detailed answers, especially for proofs.
Answered Same Day Dec 21, 2021

Solution

Robert answered on Dec 21 2021
127 Votes
1. We wish to verify the identity     ,A B C C A B     where A, B, and C are
a
itrary sets.
We have
 
   
   
   
   
definition of complement
commutativity of intersection
de Morgan's law
definition of complement
A B C
A B C
C A B
C A B
C A B
 
  
  
  
  
2. We wish to verify the identity     ,A B C C A B     where A, B, and C are
a
itrary sets, using a membership table.
In the table below, T indicates that a specific object belongs to the given set and F
indicates that it does not.
   A B C A A B A B C A B C A B
T T T F F F T F
T T F F F F T F
T F T F F F T F
T F F F F F T F
F T T T F F T F
F T F T F F T F
F F T T T T F T
F F F T T F F F
     
Since all co
esponding entries of  A B C  and  C A B  are the same, these sets
are equal.
3. We are given the set  1,2,3,4,5,6,7,8 .U  We wish to complete the following table:
 
set roster representation of set computer representation of set
3,4,5 ?
? 0,1,0,1,1,1,0,0
? ?
? ?
? ?
A
B
A
A B
A B


The computer representation of A is 0,0,1,1,1,0,0,0 since the elements 3, 4, and 5
elong to A and the elements 1, 2, 6, 7, and 8 do not.
The roster representation of B is  2,4,5,6 since the elements 2, 4, 5, and 6 belong to B
and 1, 3, 7, and 8 do not.
The roster representation of A is  1,2,6,7,8 and the computer representation is
1,1,0,0,0,1,1,1 since the elements 1, 2, 6, 7, and 8 belong to A and 3, 4, and 5 do not.
The roster representation of A B is  4,5 and the computer representation is
0,0,0,1,1,0,0,0 since the elements 4 and 5 belong to both A and B, and hence to
,A B while the elements 1, 2, 3, 6, 7, and 8 do not.
Finally, the roster representation of A B is  1,2,4,5,6,7,8 and the computer
epresentation is 1,1,0,1,1,1,1,1 since the elements 1, 2, 4, 5, 6, 7, and 8 belong to either
A or B, and hence to ,A B while the element 3 does not.
Thus we have the following completed table:
 
 
 
 
 
set roster representation of set computer representation of set
3,4,5 0,0,1,1,1,0,0,0
2,4,5,6 0,1,0,1,1,1,0,0
1,2,6,7,8 1,1,0,0,0,1,1,1
4,5...
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