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I need these problems done, show all work, I attach copy of each page of problems ·p. 27 #97,p. 37 #101, ·p. 60 #78, ·p. 63 #45, #63, ·p. 76 #57 ·p.

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I need these problems done, show all work, I attach copy of each page of problems

·p. 27 #97,p. 37 #101,

·p. 60 #78,

·p. 63 #45, #63,

·p. 76 #57

·p.

Answered Same Day Dec 22, 2021

Solution

David answered on Dec 22 2021
131 Votes
p. 27 #97:
sin(270O + n .360O)
=> sin(270O + n .360O) = sin(270O)
= sin(180O + 90O)
= -sin( 90O)
=-1
Therefore sin(270O + n .360O) = -1
p. 37 #101:
tan(3θ-4O) = 1/cot(5θ-8O)
 tan(3θ-4O) = tan(5θ-8O)
 nᴨ +3θ-4O = 5θ-8O
 2θ - 4O = nᴨ
 θ = (nᴨ + 4O)/2
 if n=0 then θ = 2O
p. 60 #78:



a) h = 1.9ft; ;
;
and S = 336ft

( )
...
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