https://webwork.math.nau.edu/webwork2/CDiggans_239/username: mka53password: Ms XXXXXXXXXX

Question

https://webwork.math.nau.edu/webwork2/CDiggans_239/username: mka53password: Ms XXXXXXXXXX

Robert · Accepted Answer

CDiggans 239 mka53 WW 09 Systems
1
u
′′
+ 4u
′
+ 6u = 0
v = u
′
v
′
= u
′′
= −4u′ − 6u
u
′
= v
v
′
= −4v − 6u
d
dt
[
u
v
]
=
[
0 1
−6 −4
] [
u
v
]
2
u
′′ − 8u′ + 6u = 7sin(3t)
v = u
′
v
′
= u
′′
= 8u
′ − 6u+ 7sin(3t)
u
′
= v
v
′
= 8v − 6u+ 7sin(3t)
d
dt
[
u
v
]
=
[
0 1
−6 8
] [
u
v
]
+
[
0
7sin(3t)
]
[
u(1)
v(1)
]
=
[
−5
−3.5
]
1
3
t2u
′′
+ 2.5tu
′
+ (t2 + 6)u = −2sin(3t)
v = u
′
v
′
= u
′′
=
−2.5tu′ − (t2 + 6)u− 2sin(3t)
t2
u
′
= v
v
′
= −2.

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