Pearson Geometry Common Core Edition 2012

Question

Rajeswari · Accepted Answer

80530 assignment
1. (3,4) is mapped to (7,-4).  This means there is reflection about x axis and horizontal shift of 4 units to right
So M’ = (10, -6) and P’ = (9,-5)
2. When reflected over line y =x, we find both x and y coordinates would change places.
Image would have coordinates as (0,0) (3,2) (3,6) and (0,4)
3. When a point (h,k) is rotated about the origin, the new coordinate would be (-h,-k) i.e. both have change of sign.
Hence A’= (-3,-3) B’=(0,0) and C’= (-3,0)
4. 
107 Part b
Practice
Constructing equilateral triangle is easier because from centre if we draw 3 lines towards circle with equal angles of 120, we would have A,B,C points.  Angle would be ½ of 120 hence 60, so equilateral triangle.
Take a paper with drawing as a circle.  Fold the paper along one diagonal first now circle is divided into two halves.  Now fold along the other perpendicular side.  That is we have made the circle into 4 equal quadrants.  The vertices would be the vertices of squares.  
This is because only in square diagonals bisect each other at right angles.

Pearson Geometry Common Core Edition 2012

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