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HI (21cm) emissions from a nearby galaxy are detected at three locations: (C) – galaxy centre (E) – -10 arcmin to the east of the galaxy center (W) –-10 arcmin to the west of the galaxy center The...

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HI (21cm) emissions from a nearby galaxy are detected at three locations: (C) – galaxy centre (E) – -10 arcmin to the east of the galaxy center (W) –-10 arcmin to the west of the galaxy center The emission peaks at XXXXXXXXXXcm at (C), XXXXXXXXXXcm at (W), and XXXXXXXXXXcm at (E). (a) For a Hubble constant of 70 km/sec/Mpc, how far away is this galaxy (in Mpc)? Calculate redshift: z = (obs / emit) /emit z = XXXXXXXXXX / 21.106) / XXXXXXXXXXz = XXXXXXXXXXCalculate distance d ~ cz/H0 d ~ (c * 0.0475) / 70 d ~ 203Mpc Distance is approx 203Mpc (b) How fast is the galaxy rotating? Assume that the galaxy is seen edge-on. f = c / w f(21.204cm) = 1.4138Ghz f(21.176cm) = 1.4157Ghz Width = XXXXXXXXXXv = XXXXXXXXXX / 1.4138) * c v = XXXXXXXXXXkm/s (c) Assuming the gas is on circular orbits, use Newton's law of gravity to determine the amount of mass in the galaxy interior to 10 arcmin radius. M = (v^2 * r) / G r = d * angle * (Pi/180) r = 1.8221x10^19 km M = 402^2 * 1.8221x10^19 / G M = 4.412x10^34 kg M = 22,181 M_sun (d) The peak brightness temperature at location (C) is 12K - what is the peak column density of this galaxy at this location?

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HI (21cm) emissions from a nearby galaxy are detected at three locations: (C) – galaxy centre (E) – -10 arcmin to the east of the galaxy center (W) –-10 arcmin to the west of the galaxy center The emission peaks at XXXXXXXXXXcm at (C), XXXXXXXXXXcm at (W), and XXXXXXXXXXcm at (E). (a) For a Hubble constant of 70 km/sec/Mpc, how far away is this galaxy (in Mpc)? Calculate redshift: z = (obs / emit) /emit z = XXXXXXXXXX / 21.106) / 21.106 z = 0.0475 Calculate distance d ~ cz/H0 d ~ (c * 0.0475) / 70 d ~ 203Mpc Distance is approx 203Mpc (b) How fast is the galaxy rotating? Assume that the galaxy is seen edge-on. f = c / w f(21.204cm) = 1.4138Ghz f(21.176cm) = 1.4157Ghz Width = 0.0019 v = XXXXXXXXXX / 1.4138) * c v = XXXXXXXXXXkm/s (c) Assuming the gas is on circular orbits, use Newton's law of gravity to determine the amount of mass in the galaxy interior to 10 arcmin radius. M = (v^2 * r) / G r = d * angle * (Pi/180) r = 1.8221x10^19 km M = 402^2 * 1.8221x10^19 / G M = 4.412x10^34 kg M = 22,181 M_sun (d) The peak brightness temperature at location (C) is 12K - what is the peak column density of this galaxy at this location? ???

Answered Same Day Dec 22, 2021

Solution

David answered on Dec 22 2021
116 Votes
HI (21cm) emissions from a nea
y galaxy are detected at three locations:
(C) – galaxy centre
(E) – -10 arcmin to the east of the galaxy center
(W) –-10 arcmin to the west of the galaxy center
The emission peaks at 21.190 cm at (C), 21.204 cm at (W), and 21.176 cm at (E).
(a) For a Hu
le constant of 70 km/sec/Mpc, how far away is this galaxy (in Mpc)?
(b) How fast is the galaxy rotating? Assume that the galaxy is seen edge-on....
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