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Microsoft Word XXXXXXXXXXFriction LAB.docx PHYS 1401 SPRING 2020 Section 2103 PHYSICS 1401 SPRING 2020 Friction1 Equipment • Calculator Objective • To compare the coefficients of static and kinetic...

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Microsoft Word XXXXXXXXXXFriction LAB.docx
PHYS 1401 SPRING 2020 Section 2103
PHYSICS 1401 SPRING 2020
Friction1
Equipment
• Calculator
Objective
• To compare the coefficients of static and kinetic friction for two given surfaces.
Introduction
Friction is a resisting force that acts along the tangent to two surfaces in contact with each other
when one body slides or attempts to slide across another. The direction of the frictional force is
opposite the body's motion or attempted motion. Our simple model is that the available
frictional force (??    or ??) is directly proportional to the normal force (??).
There are two different kinds of friction: the static friction force ??    and the kinetic friction force
??    .    
When two surfaces are still at rest, but attempt to slide one over another, static friction is
present. The static frictional force ??    is has a magnitude that can have any value, up to a limit:


??    ≤    ????     (1)
Here, ??    is the magnitude of the normal force between the surfaces.
When two surfaces are moving with respect to each other, the other kind of friction occurs. It is
the kinetic friction. The kinetic frictional force ??    has a specific magnitude:


??    =    ????     (2)
In the expressions above ??    is the static friction coefficient and ??    is the kinetic friction
coefficient. In general ??    >    ??. This means that when enough force is exerted on an object to
overcome the static frictional force and the object starts moving, the kinetic frictional force will
e less than the applied force and the object will accelerate. Another way of thinking of this is
that it is harder to get something moving than it is to keep it moving.

1 THIS LAB WAS TAKEN FROM THE PASCO EXPERIMENT MANUAL (7-FRICTION)
PHYS 1401 SPRING 2020 Section 2103
Experiment 1: Static Friction Coefficient
In this virtual experiment, you are asked to calculate the static friction coefficient of a block
sitting on the lab bench. To do this, we will consider the limit of the static friction force by
imagining that one is pulling very gently on the block until it just begin to move. Second, we
can then calculate the normal force by assuming that the table surface is perfectly horizontal so
that the normal force and gravitational forces on the block are equal in magnitude. One of the
take-home lessons from this exercise, based upon the fact that as fs,max = µsn, the slope of the
graph that denotes friction vs. normal force will generate the coefficient of static friction.
Experimental Methodology

1. For this virtual experiment you will calculate the coefficient of static friction for 2 blocks of
different mass, whose bottoms has been “roughed up” with sandpaper. Block1 has a mass of 200
grams and block2 has a mass of 300 grams. The rough side of the block is in contact with the
cable.
2. Imagine that you have tied a force sensor to your block as shown in Figure 1.



Figure 1. Schematic setup for experiment 1.

3. You place the blocks on the table. You conduct five trials and find the average value of
the force on each block. As you conduct your experiment, you gradually increase the
force on each block and observe that the block does not move until you reach a specific
value of the force in. which the block “just” begin to move. You find that that for block 1
the average force of your observations is XXXXXXXXXXN XXXXXXXXXXN. You repeat the same
procedure for block 2, making note that the average force that “just” causes the block to
move is 2.21N XXXXXXXXXXN.

4. For each block fill in the data below and perform the Data Analysis as noted below.






Mass of
Each block(kg)
Normal force
(N)

Range of
Calculated Values
for ??
Range of
Calculated
Values for ??    
(N)
Block 1
Block 2
PHYS 1401 SPRING 2020 Section 2103
Data Analysis

5. Show your calculations to determine the following:
• Calculate the normal force ??    assuming it equals the gravitational force on
the total mass.
• Calculate the range of the static frictional force based upon maximum,
minimum and mean values.
• Calculate the range of the coefficient of static friction based upon the
maximum, minimum and mean values of the frictional force values.

6. Conduct an internet search to see if you can identify the most likely material for
each block (i.e., wood, glass, steel) based upon your calculated range of values. See
eference below for a starting point in your search.
Experiment 2: Kinetic Friction Coefficient
Measuring the kinetic friction coefficient is trickier because we can only measure the pulling
force, not the friction force directly. They are only equal if the block is moving with zero
acceleration. As you are aware, it is difficult for a person to pull on the force sensor with a
zero acceleration.
However, we can construct a virtual experiment approximately emulating constant acceleration.
A block of mass ?block    (use    the    two    blocks    in    experiment    1)    is placed on the table-top, and a
weight hanger of mass ?hang    is tied to a string, which is passed over a pulley (massless,
frictionless) paired with a photogate and tied to the block, see Figure 2. When the weight
hanger is released, the entire system will accelerate and measure that acceleration.

Figure 2. Schematic setup for Experiment 2
The external forces affecting the acceleration of the system are:
• ??            pulling down on the mass hanger.
• ??    resisting the motion
PHYS 1401 SPRING 2020 Section 2103
Since these forces are in opposite directions, the sum of the forces is the difference of their
magnitudes. This must equal the total mass times the acceleration.


?net,ext    =    ?hang?    −    ??    =    ?total?     (3)

The vertical forces on the block are gravity and the normal force and assuming a perfectly
horizontal table-top, they are equal and opposite.


??    =    ?block?     (4)

So here’s the basic idea: Find ??                    for each of the blocks. Virtually, set up each block as shown in
Figure 2 and place 450 grams on the hanger for block 1 and 550 grams on the hanger for block 2.
Now, imagine that you release each block and the system approximates uniform motion.
Your virtual Smart Meter records the average acceleration values for block1 of 6.03 m/s XXXXXXXXXX
m/s2 and average acceleration values of block2 of 5.1 m/s XXXXXXXXXXm/s2 .
Experimental Setup and Data Recording

Mass of the
lock (kg)
Hanger
mass (kg) Normal
Force (N)
Average Frictional
Force (N)
Tension in
Each Cord (N)
Measured
Acceleration of
System (m/s2)
Data Analysis

1. Calculate ??     by solving Equation (3), and calculate ??    using the mass of the block.
• Solve ??    =    ????,    and    then    determine    the    average    values    of    Tension        for    each    system.    

Final Comparison
Organize the results in the summary table above. Based upon your investigations of block
materials you found in Experiment 1, do the coefficients of kinetic friction seem to match the
expected values of each material?

https:
www.engineeringtoolbox.com/friction-coefficients-d_778.html
Answered Same Day Apr 22, 2021

Solution

Sannidhya answered on Apr 23 2021
161 Votes
PHYSICS 1401 SPRING 2020
Friction
Objective:
    To compare the coefficients of static and kinetic friction for two given surfaces.
Experiment 1: Static Friction Coefficient
We are asked to calculate the static friction coefficient of a block sitting on the lab bench. To begin with, the underlying theory is as described below:
    Static friction acts between two rough surfaces when they are at rest relative to each other. It opposes any force applied on one of the surfaces with the aim of moving it. However, there is a limit till where static friction will be able to inhibit motion. This limit is given by
                fs = µsN                    -----------------------(1)
    where,
        fs is the static friction force
        µs is the static friction coefficient
        N is the normal force acting on the surface
    Once the applied force crosses this limit, relative motion will start between the surfaces.
We are given two blocks of mass 200 grams (m1 = 0.2 kg) and 300 grams (m2 = 0.3 kg) along with a force sensor to measure the external force applied on the blocks. It is also given that the average force for which the block just begins to move is 0.98 N 0.15 N for block 1 and 2.21 N 0.25 N for block 2.
(
Normal, N
)Based on the given information, the free body diagram for any of the block is as follows:
(
Gravitation, mg
) (
Static friction,
f
s
) (
F
external
)
Calculations:
· As the block is at rest, normal force equals the gravitational force. Hence, for block 1,
N1 = m1g = (0.2 kg)*(9.81 m/s2) = 1.962 N
And, for block 2,
        N2 = m2g = (0.3 kg)*(9.81 m/s2) = 2.943 N
· As the block just starts moving on application of the forces given to us, so that is the static friction force acting on the block at that instant, i.e., fs =...
SOLUTION.PDF

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