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Dr Shweta · Accepted Answer

Solved Physics questions
Answer1   Torque = Frsinϴ here torque is 510 lb in, ϴ=90° so sin90°=1 and r is 22 in
So from formula F= Ꞇ/r =510/22=23.2 lb
Answer 3   Torque = Frsinϴ 
Given F=50N, diameter=1m so radius=1/2m ϴ=90° so sin90°=1
So, Ꞇ=50x1/2 = 25Nm
Answer 4   Torque = Frsinϴ 
Here, torque is 500 lb in, ϴ=90° so sin90°=1 and r is 18 in	
 (
R
)So from formula, F= Ꞇ/r =500/18=27.

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