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For problems, the correct equation(s) is stated. The unknown is algebraically isolated. The given values are substituted in. A reasonable amount of correct steps or rationale are shown (even for...

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For problems, the correct equation(s) is stated. The unknown is algebraically isolated. The given values are substituted in. A reasonable amount of correct steps or rationale are shown (even for multiple choice). The correct answer is given, with appropriate units and direction if needed. The answer is rounded as required. All parts of the question are answered. Words and/or sketches are used to illustrate your point if appropriate. Work is laid out in a neat, readable, logical flow. For explanations, answers are as clear, specific and succinct as possible. They could be in words or diagrams or both. All parts of the question are answered. The work shows the full extent of your understanding using the relevant concepts accurately.
Answered Same Day Oct 21, 2021

Solution

Ravindra Kumar answered on Oct 22 2021
137 Votes
Solution 1
As the frequency of waves increases, the wavelength __decreases___. The range of
wavelengths for visible light is from ___380 ____ nm to ___700_______nm. Which type of
wave would penetrate the human body more easily, X-rays or gamma rays? Circle co
ect
esponse.
Reason:
We know that the relation between the frequency and the wavelength of the wave

But for the case of the monochromatic light source, if the wavelength of the light is getting change then it will not affect the frequency of the light. In that case the frequency of the light remains unchanged.
The penetration power of gamma rays higher than the penetration power of x-rays. Because we know that the frequency of the gamma rays is but the frequency of the x-rays is , hence we can say that the energy of the gamma rays is higher than the energy of the x-rays.
Solution 2
a)
Given,
Wavelength of the microwave
Speed of light
Frequency of the wave
)
Given,
Frequency
Speed of light
Solution 3
Given,
Distance
Speed of light
Time (t) =?
Here t is the time taken by the radio wave to reach the station.
So, radio wave goes to the station and come back then total distance need to travel will be times so the time taken by the radio signal will be 2t. hence the required time will be 58 sec.
Solution 4
Given,
The distance between the Proxima Centauri
a)
We know that the 1 light year
So, the distance between the Proxima Centauri and earth is
)
Speed of the spacecraft (v)
Time = distance / speed
Hence, the required time in hou

Now, converting the hour into the year.
Hence, total required time in yea
Solution 5
From the given diagram, we have sketched the ray diagram, which is given below -
a)
Here,
Image is real, diminished and inverted.
Mi
or is concave mi
o
And it is conversing the ray of light.
)
From the above ray diagram which can understand that when the object is at the centre of the concave mi
or then the image will be real, inverted and equal to the size of the object.
Hence, image is real, concave and converging.
c)
From the ray diagram, we can understand that the image is virtual and diminished. Nd the mi
or is convex mi
or and rays will be diverging.
· Virtual
· Convex mi
o
· Virtual Image
Solution 6
Given,
Height of the object
Distance between the object and the concave mi
or
Radius of the curvature of the concave mi
or
Hence, focal length of the mi
or
So,
a)
Let the distance from the mi
or to the image be v,
)
Height of the image for the concave...
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