FLUID MECHANICS WORCESTER POLYTECHNIC INSTITUTE ES3004 HOMEWORK #4 Due Tuesday June 13 by 11:59 pm...

Question

FLUID MECHANICS WORCESTER POLYTECHNIC INSTITUTE ES3004 HOMEWORK #4 Due Tuesday June 13 by 11:59 pm on Canvas. Study Chapter 5.2, XXXXXXXXXX, XXXXXXXXXXProblems: (4 points each, unless otherwise noted) 1. Problem 5.28 Hint: First find the magnitude and direction horizontal force of the fluid on the plate, the force required to hold plate stationary is of same magnitude and in opposite direction of this force. 2. Problem 5.36 Same hint as #1 3. Problem XXXXXXXXXXProblem 5.26 Same hint as #1, anchoring force is force required to hold pipe in place. 5. Problem XXXXXXXXXXProblem 5.29 Hint: Thrust reverser force is to the right. 7. Problem XXXXXXXXXXProblem 2.40 Note: The location of the resultant hydrostatic force is NOT at the plug center. See next page (6 points) 9. A home-made solid propellant rocket has an initial mass of 9.1 kg; 6.8 kg of this is fuel. The rocket is directed vertically upward from rest, burns fuel at a constant rate of 0.23 kg/s, and ejects exhaust gas at a speed of 1980 m/sec relative to the rocket. Assume that the pressure at the rocket nozzle exit is atmospheric and that air resistance may be neglected. a) Fill in the following table. You must add other important independent variables to the 1 st column; use you physical intuition and the given information above. The dependent variable in this problem is the H = rocket height after 20 secs. Independent Variable If the Independent Variable (with all other parameters held constant) Your Prediction From Physical Intuition: Does H increase (?) or decrease (?) ? Analysis Prediction: Does Your Prediction Match the Analysis Prediction: Exhaust gas velocity Ve ? Gravitational acceleration g ? ? ? ? ? Calculate; (b) the rocket velocity after 20 sec. (c) the rocket height H after 20 sec.

Robert · Accepted Answer

Ans. 5.28 
In the problem, the control volume contains the plate and flowing air as indicated in the system 
above. Application of the horizontal direction, So the linear momentum equation produced by the 
equation, 
1
1
1
1 1 1 2 2 2
2 2
2 2 1 21 2
1 2 1 1 2
2 2
2 2 2
2
3.14 3.14 3.14
4 4 4
Hence
3.14 80 20
F (40 / ) 1.23 / 1 / ( . / )
4 1000
9.27 N
x
A x
A
A x
aX
u u A u u A F
or
D D
F u u u D D
m s kg m N kg m s
F
 
  
   
 
     
 
         
 

 
 
Ans. 5.36 
 
A control volume that contains most of the plate and the water being turned by the plate, The 
application of horizontal x-direction component of the linear momentum equation produced, 
0
1 1 1 2 2 2 1 1
1
sin 20
2
AX wV V A V V A F r h A       
Now, apply the continuity principle, 
1 1 2 2
1
2 1 1
2 2
AV A V
A h
V V V
A h

 
 
From the above equation,  
     
2 2 0 21
1 1 2 2 1
2
2
2 2 01
1 1 1 1 2
2
2 23 3 2
2
0
1
( ) sin 20
2
0.5 sin 20
0.5 62.4 / 4 10 / 1.94 / 1 . / . 4
4 10
sin 20 1.94
1
AX w
AX w
AX
h
V h V h F r h
h
So
h
F r h V h V h
h
Thus
F lb ft ft ft s slugs ft lb s slug ft ft
ft ft slugs
ft s
 
 
     
 
    
 
           
  
   
  
2
3
.
1 1
.
,
213 lbAX
lb s
ft
slug ftft
So
F
  
  
   

 
 
Ans. 5.30 
 
(a) 
As shown in the figure 
The weight of including water is 1W ,

FLUID MECHANICS WORCESTER POLYTECHNIC INSTITUTE ES3004 HOMEWORK #4 Due Tuesday June 13 by 11:59 pm on Canvas. Study Chapter 5.2, XXXXXXXXXX, XXXXXXXXXXProblems: (4 points each, unless otherwise noted)...

Solution

Answer To This Question Is Available To Download

Related Questions & Answers

Submit New Assignment