(far field approximation) (far field approximation quadrupole)Radiation.

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David · Accepted Answer

%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %% 
%%                               Electric Field                         %% 
%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %% 
clc; 
clear; 
close; 
%% Program Starts here 
%The electric field due to electric dipole 
[X,Y]=meshgrid(-50:0.5:50,-50:0.5:50); 
E1=1.8.^(-1.5*sqrt(X.^2+Y.^2)).*cos(0.5*X).*sin(Y);  
E2=1.8.^(-1.5*sqrt(X.^2+Y.^2)).*cos(0.5*Y).*sin(X);  
E=E1+E2; 
%Electric field line equation 
[DX,DY]=gradient(E,2,2); 
quiver(X,Y,DX,

(far field approximation) (far field approximation quadrupole)Radiation.

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