Great Deal! Get Instant $10 FREE in Account on First Order + 10% Cashback on Every Order Order Now

Exercise 5:Aircraft Performance JetAircraft Performance (Questions 1-4) Refer to Figure 6.11 in Flight Theory and Aerodynamics (Doyle & Lewis, 1965) and assume Weight = 12,000 lb. 1.Find Climb Angle...

1 answer below »

Exercise 5:Aircraft Performance

JetAircraft Performance (Questions 1-4)

Refer to Figure 6.11 in Flight Theory and Aerodynamics(Doyle & Lewis, 1965) and assume Weight = 12,000 lb.

1.Find Climb Angle at 250 KTAS at 100 % RPM

2.Find Rate of Climb at 300 KTAS at 100 % RPM.

2.Find Max Level Airspeed at 95% RPM.

4.Find Max Range Airspeed (VBR) and Max Endurance Airspeed (VBE).

Propeller Aircraft Performance (Questions 5-8)

Refer to Figure 8.4 in Flight Theory and Aerodynamicsand assume:

· W = 20,000 lb

· S = 500 ft2

· Density Sea Level Standard Day

5.Find Max Specific Range and Max Range Airspeed (KTAS).

6.Find Max Specific Endurance and Max Endurance Airspeed (KTAS).

7.Find Max Rate of Climb and Max Rate of Climb Airspeed.

8.Find new Max Range Airspeed after fuel has burned down and W = 15,000 lb.


Landing Performance (Questions 9-14)

W = 15,000 lbCLMax = 1.5

S = 500 ft2Thrust@ Idle = 500 lb

75% of Weight on Main Tires 25 % of Weight on Nose Tire

Average Drag = 500 lbSea level standard day

9.Find Approach Speed if Vapproach = 1.2 * Vstall (KTAS) (For landing and takeoff performance use KTAS.At sea level standard day KEAS=KTAS).

10.Find Average Rolling Friction (lb) on Nose Tire during Landing Rollout if Rolling Coefficient of Friction = 0.2.

11.Find Average Braking Friction (lb) on Main Tires during Landing Rollout on Dry Concrete. Use Figure 13.9.

12.Find Average Deceleration (ft/s2) during landing rollout.Assume Lift on wing is zero during landing rollout.Account for residual Thrust, Rolling Friction, Drag, and Braking Friction.

13.Find Landing Distance Ground Roll-out (ft)

14.Find Landing Distance (ft) if Runway is at 5,000 ft Density Altitude.

Answered Same Day Dec 23, 2021

Solution

Robert answered on Dec 23 2021
128 Votes
Answe
1. Angle of Climb is defined as,
sinγ = (Ta-Tr)/W
Where Ta is available thrust at 100% RPM and Tr is minimum thrust required and W is the
weight of the aircraft
Climb of aircraft is visible when (Ta-Tr) is maximum, so from the graph given above we have,
Ta (max) = 4200lb and
Tr (min) = 830lb
W = 12,000lb so, Angle of climb will be,
sinγ = (Ta-Tr)/W
= (4200-830)/12000 =0.2808
Angle of climb is
sinγ = (Ta-Tr)/W = (4200-830)/12000 =0.2808
γ =16.31
0
(Answer)
2. Rate of climb is defined as ,
Rate of Climb = 101.3*Vk* Sinγ
Given that,
At 300 KTAS from the graph we can determine its Ta and Tr
Thrust Available is Ta =4200lb while thrust required is Tr =1000lb
So, Rate of climb is,
Rate of Climb = 101.3*Vk* Sinγ = 101.3*300*(4200-1000)/12000
Rate of Climb =8104 ft/min (Answer)
3. Now the question asks about 95% RPM from the graph it is clearly visible that the
maximum level air speed is ,
So,
Vmax = 500 KTAS (Answer)
4. Now we need to calculate two different speeds maximum edurance and maximum Range
speed and this can be calculated fron the graph with the use of their definitions,
Max endurance airspeed V (BE) occurs when minimum thrust is required so at
Tr is minimum the speed is
V (BE) = 240 KTAS (Answer)
While for the Maximum Range speed we have,
Maximum range speed is equal to the value where the straight line drawn from the origin
intersects the graph. (Look for the graph)
So,
V (BR) will be 300 KTAS (Answer)
Answe
5. As done previously Max range airspeed occurs V(BR) occurs when the straight line
drawn from the origin intersects the graph given so if we give a look to the graph we
have,
V...
SOLUTION.PDF

Answer To This Question Is Available To Download

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here