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ex111(1) a-c-e ex XXXXXXXXXXa-c-e 3-4-5 ex33 (6)

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Answered Same Day Dec 23, 2021

Solution

David answered on Dec 23 2021
117 Votes
Answe
1. (a)
f(x) = x5/3
For the above function for x y
f(x) f(y)
Hence f(x) is one to one function.
1. (c)
Let x1 and x2 are real numbers, such that f(x1) = f(x2) , then
f(x1) = 3x1 + 5 = f(x2) = 3x2+5
so, we get
x1 = x2
Therefore f(x) is one to one and onto as well.
f(x) and f-1(x) both are differentiable so continuous as well so it is homeomorphism.
1(e)
f(x) = 1/x
Let x1 and x2 are real numbers, such that f(x1) = f(x2) , then
f(x1) = 1/x1 = f(x2) = 1/x2
so, we get
x1 = x2
Therefore f(x) is one to one and onto as well.
f(x) and f-1(x) both are differentiable so continuous as well so it is homeomorphism.
Answer
2. (a)
Here since no boundaries are given for the variable x on domain R, so it is an open set.
2. (c)
Here in this case,
x = 1/n where n is some natural number, hence
So since both domain and range on the function is not known so it is neither a closed nor an open set.
2. (e)
x*sin(1/x) = 0 is a closed set as for only selected values it...
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