Electrons with momentum 330 MeV/c are
elastically scattered through an angle of 100 by a nucleus of...

Question

Electrons with momentum 330 MeV/c are
elastically scattered through an angle of 100 by a nucleus of 56Fe. If the
charge distribution on the nucleus is that of a uniform hard sphere, and assuming
the Born approximation is valid, by what factor would you expect the Mott
cross-section to be reduced?

Baljit · Accepted Answer

We have given Momentum of Electron po =330MeV/c
Angle of Scattering Ѳ=10o
We know that Form Factor is given by
   F(q2)=3 [ sin(b(r))- b(r) cos(b(r))]b-3
Here b(r)=    and  a=1.

Electrons with momentum 330 MeV/c are elastically scattered through an angle of 100 by a nucleus of 56Fe. If the charge distribution on the nucleus is that of a uniform hard sphere, and assuming the...

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